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  • 2019牛客暑期多校训练营(第五场)- generator 1

    矩阵快速幂

    把指数按十进制拆开的快速幂。。。

    #include <bits/stdc++.h>
    #define INF 0x3f3f3f3f
    #define full(a, b) memset(a, b, sizeof a)
    #define __fastIn ios::sync_with_stdio(false), cin.tie(0)
    #define pb push_back
    using namespace std;
    typedef long long LL;
    inline int lowbit(int x){ return x & (-x); }
    inline int read(){
        int ret = 0, w = 0; char ch = 0;
        while(!isdigit(ch)){
            w |= ch == '-', ch = getchar();
        }
        while(isdigit(ch)){
            ret = (ret << 3) + (ret << 1) + (ch ^ 48);
            ch = getchar();
        }
        return w ? -ret : ret;
    }
    inline int lcm(int a, int b){ return a / __gcd(a, b) * b; }
    template <typename A, typename B, typename C>
    inline A fpow(A x, B p, C lyd){
        A ans = 1;
        for(; p; p >>= 1, x = 1LL * x * x % lyd)if(p & 1)ans = 1LL * x * ans % lyd;
        return ans;
    }
    LL x0, x1, a, b, p;
    string n;
    struct Matrix{
        LL m[2][2];
        Matrix(){
            full(m, 0);
        }
        Matrix operator * (Matrix &a){
            Matrix ret;
            for(int i = 0; i < 2; i ++){
                for(int j = 0; j < 2; j ++){
                    for(int k = 0; k < 2; k ++){
                        ret.m[i][j] = ret.m[i][j] + (m[i][k] * a.m[k][j] % p);
                        if(ret.m[i][j] >= p) ret.m[i][j] -= p;
                    }
                }
            }
            return ret;
        }
    };
    Matrix ori, t, e;
    inline void init(){
        e.m[0][0] = e.m[1][1] = 1;
        ori.m[0][0] = x1, ori.m[1][0] = x0;
        t.m[0][0] = a, t.m[0][1] = b, t.m[1][0] = 1;
    }
    
    inline Matrix fpow(Matrix &a, const string &n){
        Matrix ret = e;
        for(int i = n.size() - 1; i >= 0; i --){
            int y = n[i] - '0';
            while(y --) ret = ret * a;
            Matrix tr = a * a;
            a = tr * tr;
            a = a * a * tr;
            //for(int j = 1; j <= 9; j ++) a = a * tr;
    
        }
        return ret;
    }
    
    int main(){
    
        __fastIn;
    
        cin >> x0 >> x1 >> a >> b;
        cin >> n >> p;
        init();
        t = fpow(t, n);
        ori = t * ori;
        cout << (ori.m[1][0] % p) << endl;
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/onionQAQ/p/11294161.html
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