zoukankan      html  css  js  c++  java
  • 495. Teemo Attacking

    1. Question:

    495. Teemo Attacking

    https://leetcode.com/problems/teemo-attacking/

    In LOL world, there is a hero called Teemo and his attacking can make his enemy Ashe be in poisoned condition. Now, given the Teemo's attacking ascending time series towards Ashe and the poisoning time duration per Teemo's attacking, you need to output the total time that Ashe is in poisoned condition.

    You may assume that Teemo attacks at the very beginning of a specific time point, and makes Ashe be in poisoned condition immediately.

    Example 1:

    Input: [1,4], 2
    Output: 4
    Explanation: At time point 1, Teemo starts attacking Ashe and makes Ashe be poisoned immediately. 
    This poisoned status will last 2 seconds until the end of time point 2.
    And at time point 4, Teemo attacks Ashe again, and causes Ashe to be in poisoned status for another 2 seconds.
    So you finally need to output 4.

    Example 2:

    Input: [1,2], 2
    Output: 3
    Explanation: At time point 1, Teemo starts attacking Ashe and makes Ashe be poisoned. 
    This poisoned status will last 2 seconds until the end of time point 2.
    However, at the beginning of time point 2, Teemo attacks Ashe again who is already in poisoned status.
    Since the poisoned status won't add up together, though the second poisoning attack will still work at time point 2, it will stop at the end of time point 3.
    So you finally need to output 3.

    Note:

    1. You may assume the length of given time series array won't exceed 10000.
    2. You may assume the numbers in the Teemo's attacking time series and his poisoning time duration per attacking are non-negative integers, which won't exceed 10,000,000.

    2. Solution:

    class Solution:
        def findPoisonedDuration(self, timeSeries, duration):
            """
            :type timeSeries: List[int]
            :type duration: int
            :rtype: int
            """
            if timeSeries is None or len(timeSeries) <=0:
                return 0
    
            total_time = duration
    
            for i in range(1,len(timeSeries)):
                time_duration = timeSeries[i] - timeSeries[i-1]
                total_time += duration
                if time_duration < duration:
                    total_time -= duration - time_duration
    
            return total_time

    3. Complexity Analysis

    Time Complexity : O(N)

    Space Complexity: O(1)

  • 相关阅读:
    3D酷炫翻牌效果
    鼠标的默认事件之oncontextmenu及其案例
    键盘事件之keyCode
    用js和jQuery分别实现选项卡功能
    js中事件的绑定与解绑:attachEvent/detachEvent、addEventListener/removeEventListener
    js中的键盘事件:onkeydown、onkeypress、onkeyup
    用javaDBF操作(读、写)DBF文件
    Linux-tar命令
    动态查询
    java中对list进行分页显示数据到页面
  • 原文地址:https://www.cnblogs.com/ordili/p/10004607.html
Copyright © 2011-2022 走看看