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  • Children’s Queue

    Children’s Queue

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 10040    Accepted Submission(s): 3198


    Problem Description
    There are many students in PHT School. One day, the headmaster whose name is PigHeader wanted all students stand in a line. He prescribed that girl can not be in single. In other words, either no girl in the queue or more than one girl stands side by side. The case n=4 (n is the number of children) is like
    FFFF, FFFM, MFFF, FFMM, MFFM, MMFF, MMMM
    Here F stands for a girl and M stands for a boy. The total number of queue satisfied the headmaster’s needs is 7. Can you make a program to find the total number of queue with n children?
     

    Input
    There are multiple cases in this problem and ended by the EOF. In each case, there is only one integer n means the number of children (1<=n<=1000)
     

    Output
    For each test case, there is only one integer means the number of queue satisfied the headmaster’s needs.
     

    Sample Input
    1 2 3
     

    Sample Output
    1 2 4
    #include<iostream>
    #include<iomanip>
    using namespace std;
    int main()
    {
    	int n;
    	int f[1001][101] = {0};
    	f[0][1]=1;
    	f[1][1]=1;
    	f[2][1]=2;
    	f[3][1]=4;
    	for(int i=4; i<1001; ++i)
    	{
    		for(int j=1;j<101;++j)
    		{
    			f[i][j]+=f[i-1][j]+f[i-2][j]+f[i-4][j];
    			f[i][j+1]+=f[i][j]/10000;	
    			f[i][j]%=10000;	
    		}
    	}
    	
    	while(cin>>n)
    	{int j=100;
    	while(!f[n][j])
    	{j--;}	
    	cout<<f[n][j];
    	j--;
    	for(;j>0;j--)
    		printf("%04d", f[n][j]);
    	cout<<endl;
    
    	
    	}
    	
    	return 0;
    }


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  • 原文地址:https://www.cnblogs.com/oversea201405/p/3766958.html
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