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  • Add Two Numbers

    You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

    Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
    Output: 7 -> 0 -> 8

    简单链表题

    /**
     * Definition for singly-linked list.
     * struct ListNode {
     *     int val;
     *     ListNode *next;
     *     ListNode(int x) : val(x), next(NULL) {}
     * };
     */
    class Solution {
    public:
        ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {
            int flag = 0;
            if(l1 == NULL && l2 == NULL)return NULL;
     
            ListNode * head = new ListNode(0);
            ListNode * tmp =head;
            
            while(l1!=NULL && l2!=NULL)
            {
                int temp = l1->val + l2->val + flag;
                flag = temp/10;
                ListNode *node = new ListNode(temp%10);
                tmp->next = node;
                tmp = tmp -> next;
                l1 = l1->next;
                l2 = l2->next;
            }
            while(l1!=NULL)
            {
                int temp = l1->val + flag;
                flag = temp/10;
                ListNode *node = new ListNode(temp%10);
                tmp->next = node;
                tmp = tmp -> next;
                l1 = l1->next;
            }
            while(l2!=NULL)
            {
                int temp = l2->val + flag;
                flag = temp/10;
                ListNode *node = new ListNode(temp%10);
                tmp->next = node;
                tmp = tmp -> next;
                l2 = l2->next;
            }
            if(flag == 1)
            {
                ListNode *node = new ListNode(1);
                tmp->next = node;
            }
            head =head->next;
            return head;
            
        }
    };
    

      

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  • 原文地址:https://www.cnblogs.com/pengyu2003/p/3581887.html
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