zoukankan      html  css  js  c++  java
  • leetcode------Jump Game II

    标题: Jump Game II
    通过率: 24.5
    难度:

    Given an array of non-negative integers, you are initially positioned at the first index of the array.

    Each element in the array represents your maximum jump length at that position.

    Your goal is to reach the last index in the minimum number of jumps.

    For example:
    Given array A = [2,3,1,1,4]

    The minimum number of jumps to reach the last index is 2. (Jump 1 step from index 0 to 1, then 3 steps to the last index.)

    贪心算法

    每次遍历一遍可以到达的最远距离之内的所有节点,找出可以到达的最远节点,然后继续找,

    每走一个最远就加一步

     1 public class Solution {
     2     public int jump(int[] A) {
     3         int step=0,lastMax=0,max=0;
     4         for(int i=0;i<A.length;){
     5             if(lastMax>=A.length-1)break;
     6             while(i<=lastMax){
     7                 if(i+A[i]>max){
     8                     max=i+A[i];
     9                 }
    10                 i++;
    11             }
    12             if(lastMax<max){
    13                 lastMax=max;
    14             }
    15             step++;
    16         }
    17         return step;
    18     }
    19 }
  • 相关阅读:
    10.19的一些题
    10.18 模拟赛
    bzoj 2212 Tree Rotations
    10.11的一些题
    10.15 模拟赛
    bzoj 5329 战略游戏
    php面向对象基础(二)
    php面向对象基础(一)
    PHP基础-数组与数据结构
    php基础-字符串处理
  • 原文地址:https://www.cnblogs.com/pkuYang/p/4375848.html
Copyright © 2011-2022 走看看