hdoj--5567--sequence1(水题)

sequence1

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 345    Accepted Submission(s): 254

Problem Description

Given an array a with length n, could you tell me how many pairs (i,j) ( i < j ) for abs(ai−aj) mod b=c.

 

Input

Several test cases(about 5)

For each cases, first come 3 integers, n,b,c(1≤n≤100,0≤c<b≤109)

Then follows n integers ai(0≤ai≤109)

 

Output

For each cases, please output an integer in a line as the answer.

 

Sample Input

3 3 2
1 2 3
3 3 1
1 2 3

 

Sample Output

1
2

 

Source

BestCoder Round #63 (div.2)

 

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#include<stdio.h>
#include<string.h>
#include<math.h>
int n,b,c;
long long a[1010];
bool judge(long long x,long long y)
{
	if(abs(x-y)%b==c)
	return true;
	return false; 
}
int main()
{
	while(scanf("%d%d%d",&n,&b,&c)!=EOF)
	{
		memset(a,0,sizeof(a));
		for(int i=0;i<n;i++)
		scanf("%lld",&a[i]);
		int sum=0;
		for(int i=0;i<n;i++)
		{
			for(int j=i+1;j<n;j++)
			{
				if(judge(a[i],a[j]))
				sum++;
			}
		}
		printf("%d
",sum);
	}
	return 0;
}