SQL中Group分组获取Top N 方法实现

有产品表，包含id，name，city，addtime四个字段，因报表需要按城市分组，统计每个城市的最新10个产品，便向该表中插入了100万数据，做了如下系列测试：

CREATE TABLE [dbo].[products](
    [id] [int] IDENTITY(1,1) NOT NULL,
    [name] [nvarchar](50) NULL,
    [addtime] [datetime] NULL,
    [city] [nvarchar](10) NULL,
 CONSTRAINT [PK_products] PRIMARY KEY CLUSTERED 
(
    [id] ASC
)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]

1、采用row_number方法，执行5次，平均下来8秒左右，速度最快。

select no, id,name,city 
from  (select  no =row_number() over (partition by city order by addtime desc), * from products)t
where no< 11 order by city asc,addtime desc

2、采用cross apply方法，执行了3次，基本都在3分5秒以上，已经很慢了。

select distinct b.id,b.name,b.city from products a 
cross apply (select top 10 * from products where city = a.city order by  addtime desc) b

3、采用Count查询，只执行了两次，第一次执行到5分钟时，取消任务执行了；第二次执行到13分钟时，没有hold住又直接停止了，实在无法忍受。

select id,name,city from products a 
where (  select count(city) from products where a.city = city and addtime>a.addtime) < 10
order by city asc,addtime desc

4、采用游标方法，这个最后测试的，执行了5次，每次都是10秒完成，感觉还不错。

declare @city nvarchar(10)
create table #Top(id int,name nvarchar(50),city nvarchar(10),addtime datetime)
declare mycursor cursor for
select  distinct city from products order by city asc
open mycursor
fetch next from mycursor into @city
while @@fetch_status =0
begin
    insert into #Top 
    select top 10 id,name,city,addtime from products where city = @city 
    fetch next from mycursor into @city
end 
close mycursor
deallocate mycursor
Select * from #Top order by city asc,addtime desc
drop table #Top

通过上述对比不难发现，在面临Group获取Top N场景时，可以首选row_number，游标cursor其次，另外两个就基本不考虑了，数据量大的时候根本没法使用。