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  • 379. Design Phone Directory

    题里没说get的时候应该随机选取还是,选取least available number,题里似乎是后者,就按后者做。

    用SET来判断是否被占用,STACK保存可用的号码,好像就是这样,用QUEUE也试了一下,比STACK慢,不知道为什么,估计跟具体的CASE有关吧。。

    public class PhoneDirectory {
    
        /** Initialize your data structure here
            @param maxNumbers - The maximum numbers that can be stored in the phone directory. */
            
        Set<Integer> set;
        Stack<Integer> stk;
        int max;
        int cur = 0;
        public PhoneDirectory(int maxNumbers) 
        {
            max = maxNumbers;
            set = new HashSet<Integer>();
            stk = new Stack<Integer>();
            for(int i =0; i < max;i++) stk.push(i);
        }
        
        /** Provide a number which is not assigned to anyone.
            @return - Return an available number. Return -1 if none is available. */
        public int get() 
        {
            if(stk.isEmpty()) return -1;
            
            set.add(stk.peek());
            
            return stk.pop();
            
                
        }
        
        /** Check if a number is available or not. */
        public boolean check(int number) {
            return !set.contains(number);
        }
        
        /** Recycle or release a number. */
        public void release(int number) 
        {
            if(set.contains(number))
            {
                stk.push(number);
                set.remove(number);
            }
            
           
            
        }
    }
    
    /**
     * Your PhoneDirectory object will be instantiated and called as such:
     * PhoneDirectory obj = new PhoneDirectory(maxNumbers);
     * int param_1 = obj.get();
     * boolean param_2 = obj.check(number);
     * obj.release(number);
     */
    
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  • 原文地址:https://www.cnblogs.com/reboot329/p/5951374.html
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