【leetcode】【141】Linked List Cycle

#include<iostream>
using namespace std;

struct ListNode {
	int val;
	ListNode *next;
	ListNode(int x) : val(x), next(NULL) {}
};

class Solution {
public:
	bool hasCycle(ListNode *head) {
		if (head == NULL || head->next == NULL) //链表空或只有一个节点
			return false;

		ListNode* slow = head;
		ListNode* fast = head;
		while (fast&&fast->next){
			slow = slow->next;
			fast = fast->next->next;
			if (slow == fast)
				return true;
		}
		return false;
	}
	ListNode* createList(ListNode* head){
		int numOfNode;
		int value;
		cout << "please input number of listNode:";
		cin >> numOfNode;
		cin >> value;
		head = new ListNode(value);
		ListNode* cur = head;
		for (int i = 1; i < numOfNode; ++i){
			cin >> value;
			ListNode* temp = new ListNode(value);
			cur->next = temp;
			cur = temp;
		}
		//cur->next = head;
		return head;
	}
	void printNode(ListNode* head){
		ListNode* cur = head;
		while (cur){
			cout << cur->val << " ";
			cur = cur->next;
		}
		cout << endl;
	}
};

int main(){
	ListNode* head = NULL;
	Solution lst;
	head = lst.createList(head);
	//lst.printNode(head);

	cout << boolalpha << lst.hasCycle(head) << endl;

	system("pause");
	return 0;
}

参考：http://blog.sina.com.cn/s/blog_725dd1010100tqwp.html