hdu-2055

题目：http://acm.hdu.edu.cn/showproblem.php?pid=2055

An easy problem

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 21202    Accepted Submission(s): 14050

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

 

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

 

Output

for each case, you should the result of y+f(x) on a line.

 

Sample Input

6 R 1 P 2 G 3 r 1 p 2 g 3

 

Sample Output

19 18 10 -17 -14 -4

 

Author

8600

 

思路：用字符串输入后，把字母转化成对应的数字，再相加

 

难度：这个也是简单的

 

代码：

#include<stdio.h>
int main()
{
    int n,i,a;
    char s;
    while(scanf("%d",&n)!=EOF)
    {
        getchar();
        for(i=0;i<n;i++)
        {
            scanf("%c%d",&s,&a);
            getchar();
            if(s>='A'&&s<='Z')
                printf("%d
",s-64+a);
            else printf("%d
",96-s+a);
        }
    }
    return 0;
}