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  • LA 4992 Jungle Outpost(半平面交)

    Jungle Outpost

    【题目链接】Jungle Outpost

    【题目类型】半平面交

    &题解:

    蓝书282 我自己写的代码居然AC了!!!
    刘汝佳的说要right要-3什么的,还要特判3,我感觉就不需要,所以我就没写,交了一发,想着应会wa吧,结果居然tmA了!!!

    &代码:

    #include <cstdio>
    #include <algorithm>
    #include <cmath>
    #include <vector>
    using namespace std;
    
    struct Point {
    	double x, y;
    	Point(double x = 0, double y = 0): x(x), y(y) {}
    };
    typedef Point Vector;
    
    Vector operator + (Vector A, Vector B) { return Vector(A.x + B.x, A.y + B.y); }
    Vector operator - (Vector A, Vector B) { return Vector(A.x - B.x, A.y - B.y); }
    Vector operator * (Vector A, double p) { return Vector(A.x * p, A.y * p); }
    bool operator < (Point a, Point b) { return a.x < b.x || (a.x == b.x && a.y < b.y); }
    double Cross(Vector A, Vector B) { return A.x * B.y - A.y * B.x; }
    
    double PolygonArea(vector<Point> p) {
    	int n = p.size();
    	double ans = 0;
    	for(int i = 1; i < n - 1; i++) {
    		ans += Cross(p[i] - p[0], p[i + 1] - p[0]);
    	}
    	return ans / 2;
    }
    
    struct Line {
    	Point p, v;
    	double ang;
    	Line() {}
    	Line(Point p, Vector v): p(p), v(v) { ang = atan2(v.y, v.x); }
    	bool operator <(const Line& l) const {
    		return ang < l.ang;
    	}
    };
    
    const double eps = 1e-9;
    
    bool OnLeft(Line l, Point p) {
    	//bug 是p-l.p  不是l.p-p
    	return Cross(l.v, p - l.p) > 0;
    }
    Point LineInter(Line a, Line b) {
    	Vector u = a.p - b.p;
    	double t = Cross(b.v, u) / Cross(a.v, b.v);
    	return a.p + a.v * t;
    }
    
    vector<Point> HalfplaneIntersection(vector<Line> L) {
    	int n = L.size();
    	sort(L.begin(), L.end());
    	int first, last;
    	vector<Point> p(n), ans;
    	vector<Line> que(n);
    	que[first = last = 0] = L[0];
    	for(int i = 1; i < n; i++) {
    		while(first < last && !OnLeft(L[i], p[last - 1])) last--;
    		while(first < last && !OnLeft(L[i], p[first])) first++;
    		que[++last] = L[i];
    		if(fabs(Cross(que[last].v, que[last - 1].v)) < eps) {
    			last--;
    			if(OnLeft(que[last], L[i].p)) que[last] = L[i];
    		}
    		if(first < last) p[last - 1] = LineInter(que[last], que[last - 1]);
    	}
    	while(first < last && !OnLeft(que[first], p[last - 1])) last--;
    	if(last - first <= 1) return ans;
    	p[last] = LineInter(que[first], que[last]);
    	for(int i = first; i <= last; i++) {
    		ans.push_back(p[i]);
    	}
    	return ans;
    }
    
    int main() {
    	//("E:1.in", "r", stdin);
    	int n;
    	while(~scanf("%d", &n)) {
    		vector<Point> p;
    		int x, y;
    		for(int i = 0; i < n; i++) {
    			scanf("%d%d", &x, &y);
    			p.push_back(Point(x, y));
    		}
    		reverse(p.begin(), p.end());
    		int left = 0, right = n;
    		while(left <= right) {
    			int mid = left + right >> 1;
    			vector<Line> L;
    			for(int i = 0; i < n; i++) {
    				L.push_back(Line(p[i], p[(i + mid + 1) % n] - p[i]));
    			}
    			vector<Point> pp = HalfplaneIntersection(L);
    			if(pp.empty()) right = mid - 1;
    			else left = mid + 1;
    			// printf("%d   %d   %d 
    ", left, mid, right);
    		}
                    //这要输出了答案是left 跟right没有关系
    		printf("%d
    ", left);
    		// printf("%d
    ", right);
    	}
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/s1124yy/p/6809858.html
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