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  • MySQL练习

    一、表关系

    二、创建数据库和表

    (一)创建数据库

    创建数据库test2,用于存放上述表

    mysql> create database test2 default charset utf8 collate utf8_general_ci;
    Query OK, 1 row affected (0.00 sec)

    (二)创建表

    创建上述表以及相应的约束

    • 创建班级表
    mysql> create table class (
        ->  cid int primary key auto_increment comment '主键ID' ,
        ->  caption varchar(64) not null comment '班级名称'
        -> )charset=utf8 collate=utf8_general_ci engine=innodb comment='班级表
    Query OK, 0 rows affected (0.02 sec)
    
    mysql> show tables;
    +-----------------+
    | Tables_in_test2 |
    +-----------------+
    | class           |
    +-----------------+
    1 row in set (0.00 sec)
    
    mysql> desc class;
    +---------+-------------+------+-----+---------+----------------+
    | Field   | Type        | Null | Key | Default | Extra          |
    +---------+-------------+------+-----+---------+----------------+
    | cid     | int(11)     | NO   | PRI | NULL    | auto_increment |
    | caption | varchar(64) | NO   |     | NULL    |                |
    +---------+-------------+------+-----+---------+----------------+
    2 rows in set (0.01 sec)
    • 创建学生表
    mysql>   create table student(
        ->   sid int primary key auto_increment comment '主键ID',
        ->   sname varchar(32) not null comment '学生名字',
        ->   gender enum('','') not null default '' comment '性别',
        ->   class_id int comment '关联班级外键',
        ->  constraint fk_student_class foreign key(class_id) references class(cid)
        -> )charset=utf8 collate=utf8_general_ci engine=innodb comment '学生表';
    Query OK, 0 rows affected (0.03 sec)
    
    mysql> show tables;
    +-----------------+
    | Tables_in_test2 |
    +-----------------+
    | class           |
    | student         |
    +-----------------+
    2 rows in set (0.00 sec)
    
    mysql> desc student;
    +----------+-----------------+------+-----+---------+----------------+
    | Field    | Type            | Null | Key | Default | Extra          |
    +----------+-----------------+------+-----+---------+----------------+
    | sid      | int(11)         | NO   | PRI | NULL    | auto_increment |
    | sname    | varchar(32)     | NO   |     | NULL    |                |
    | gender   | enum('','') | NO   |     ||                |
    | class_id | int(11)         | YES  | MUL | NULL    |                |
    +----------+-----------------+------+-----+---------+----------------+
    4 rows in set (0.01 sec)
    • 创建教师表
    mysql> create table teacher(
        -> tid int primary key auto_increment comment '主键ID',
        -> tname varchar(32) comment '老师名字'
        -> )charset=utf8 collate=utf8_general_ci engine=innodb comment='教师表';
    Query OK, 0 rows affected (0.02 sec)
    
    mysql> desc teacher;
    +-------+-------------+------+-----+---------+----------------+
    | Field | Type        | Null | Key | Default | Extra          |
    +-------+-------------+------+-----+---------+----------------+
    | tid   | int(11)     | NO   | PRI | NULL    | auto_increment |
    | tname | varchar(32) | YES  |     | NULL    |                |
    +-------+-------------+------+-----+---------+----------------+
    2 rows in set (0.01 sec)
    • 创建课程表
    mysql> create table course(
        -> cid int primary key auto_increment comment '课程表',
        -> cname varchar(32) comment '课程名称',
        -> unique index_cname(cname),
        -> teacher_id int comment '关联教师表的外键',
        -> constraint fk_course_teacher foreign key(teacher_id) references teacher(t
    id)
        -> )charset=utf8 collate=utf8_general_ci engine=innodb comment='课程表';
    Query OK, 0 rows affected (0.03 sec)
    
    mysql> desc course;
    +------------+-------------+------+-----+---------+----------------+
    | Field      | Type        | Null | Key | Default | Extra          |
    +------------+-------------+------+-----+---------+----------------+
    | cid        | int(11)     | NO   | PRI | NULL    | auto_increment |
    | cname      | varchar(32) | YES  | UNI | NULL    |                |
    | teacher_id | int(11)     | YES  | MUL | NULL    |                |
    +------------+-------------+------+-----+---------+----------------+
    3 rows in set (0.01 sec)
    • 创建成绩表
    mysql> create table score(
        ->      sid int primary key auto_increment comment '成绩表',
        ->      student_id int comment '添加关联学生表的外键字段',
        ->   constraint fk_score_student foreign key(student_id) references student(sid),
        ->      course_id int comment '添加关联课程表的外键字段',
        ->   constraint fk_score_course foreign key(course_id) references course(cid),
        ->      unique index_together(student_id,course_id) comment '将学生和成绩进行联合唯一索引',
        ->      number float(255,2) comment '学生成绩'
        ->      )charset=utf8 collate=utf8_general_ci engine=innodb comment='成绩表';
    Query OK, 0 rows affected (0.03 sec)
    
    mysql> desc score;
    +------------+--------------+------+-----+---------+----------------+
    | Field      | Type         | Null | Key | Default | Extra          |
    +------------+--------------+------+-----+---------+----------------+
    | sid        | int(11)      | NO   | PRI | NULL    | auto_increment |
    | student_id | int(11)      | YES  | MUL | NULL    |                |
    | course_id  | int(11)      | YES  | MUL | NULL    |                |
    | number     | float(255,2) | YES  |     | NULL    |                |
    +------------+--------------+------+-----+---------+----------------+
    4 rows in set (0.01 sec)

    三、创建测试数据

    • 班级表添加数据
    mysql> insert into class(caption)values('三年二班'),('一年三班'),('三年一班');
    Query OK, 3 rows affected (0.00 sec)
    Records: 3  Duplicates: 0  Warnings: 0
    • 学生表添加数据
    mysql> insert into student(sname,gender,class_id) values('钢蛋','',1),('铁锤',
    '',1),('山炮','',2);
    Query OK, 3 rows affected (0.00 sec)
    Records: 3  Duplicates: 0  Warnings: 0
    • 教师表添加数据
    mysql> insert into teacher(tname) values('波多'),('苍空'),('饭岛');
    Query OK, 3 rows affected (0.00 sec)
    Records: 3  Duplicates: 0  Warnings: 0
    • 课程表添加数据
    mysql> insert into course(cname,teacher_id) values('生物',1),('体育',1),('物理',2);
    Query OK, 3 rows affected (0.00 sec)
    Records: 3  Duplicates: 0  Warnings: 0
    • 成绩表添加数据
    mysql> insert into score(student_id,course_id,number) values(1,1,60),(1,2,59),(2
    ,2,100);
    Query OK, 3 rows affected (0.00 sec)
    Records: 3  Duplicates: 0  Warnings: 0

    四、操作数据表

    1、查询“生物”课程比“物理”课程成绩高的所有学生的学号

    分析:先查出所有生物课程成绩的学生;其次查出所有物理课程成绩的学生;最后将上述两个结果进行相连通过where语句查出符合要求的学生

    #查出生物相关成绩的学生
    mysql> select s.student_id,c.cname,s.number from course c left join score s on c
    .cid=s.course_id where c.cname='生物';
    +------------+-------+--------+
    | student_id | cname | number |
    +------------+-------+--------+
    |          1 | 生物  |  60.00 |
    +------------+-------+--------+
    1 row in set (0.00 sec)
    
    #查出物理成绩相关学生
    mysql> select s.student_id,c.cname,s.number from course c left join score s on c
    .cid=s.course_id where c.cname='物理';
    +------------+-------+--------+
    | student_id | cname | number |
    +------------+-------+--------+
    |       NULL | 物理  |   NULL |
    +------------+-------+--------+
    1 row in set (0.00 sec)
    
    #查出符合条件的结果
    mysql> select d.student_id,d.cname,d.number  from (select s.student_id,c.cname,s
    .number from course c left join score s on c.cid=s.course_id where c.cname='生物')as d
        -> left join (select s.student_id,c.cname,s.number from course c left join 
    score s
    on c.cid=s.course_id where c.cname='物理') as e on d.student_id=e.student _id where -> d.number > ifnull(e.number,0); +------------+-------+--------+ | student_id | cname | number | +------------+-------+--------+ | 1 | 生物 | 60.00 | +------------+-------+--------+ 1 row in set (0.01 sec) mysql>

    2、查询平均成绩大于60分的同学的学号和平均成绩

    分析:

    • 先查出所有同学的学号、各科成绩;
    • 其次是分组,根据学生的学号进行分组;
    • 计算出每一个学生的平均成绩;
    • 平均成绩大于60分的筛选出来;
    #查出所有学生的学号和各科目的成绩
    mysql> select sc.student_id,sc.course_id,number from student st left join score
    sc on st.sid = sc.student_id;
    +------------+-----------+--------+
    | student_id | course_id | number |
    +------------+-----------+--------+
    |          1 |         1 |  60.00 |
    |          1 |         2 |  59.00 |
    |          2 |         2 | 100.00 |
    |       NULL |      NULL |   NULL |
    +------------+-----------+--------+
    4 rows in set (0.00 sec)
    
    #进行分组
    mysql> select sc.student_id,sc.course_id,number from student st left join score
    sc on st.sid = sc.student_id group by sc.student_id;
    +------------+-----------+--------+
    | student_id | course_id | number |
    +------------+-----------+--------+
    |       NULL |      NULL |   NULL |
    |          1 |         1 |  60.00 |
    |          2 |         2 | 100.00 |
    +------------+-----------+--------+
    
    #计算每一个学生的平均成绩
    mysql> select sc.student_id,sc.course_id,number,avg(number) from student st left
     join score sc on st.sid = sc.student_id group by sc.student_id;
    +------------+-----------+--------+-------------+
    | student_id | course_id | number | avg(number) |
    +------------+-----------+--------+-------------+
    |       NULL |      NULL |   NULL |        NULL |
    |          1 |         1 |  60.00 |   59.500000 |
    |          2 |         2 | 100.00 |  100.000000 |
    +------------+-----------+--------+-------------+
    3 rows in set (0.00 sec)
    
    #筛选出最后的结果
    mysql> select sc.student_id,sc.course_id,number,avg(number) as stu_avg from stud
    ent st left join score sc on st.sid = sc.student_id group by sc.student_id havin
    g stu_avg > 60;
    +------------+-----------+--------+------------+
    | student_id | course_id | number | stu_avg    |
    +------------+-----------+--------+------------+
    |          2 |         2 | 100.00 | 100.000000 |
    +------------+-----------+--------+------------+
    1 row in set (0.00 sec)

    3、查询所有同学的学号、姓名、选课数、总成绩

    分析:

    • 查询所有的学生信息
    • 在进行统计选课数、总成绩时是针对每一个学生,所以必须以学生学号进行分组
    • 统计出最后的结果
    mysql> select sc.student_id,st.sname,count(sc.course_id),sum(number) from studen
    t st left join score sc on st.sid = sc.student_id group by sc.student_id;
    +------------+-------+---------------------+-------------+
    | student_id | sname | count(sc.course_id) | sum(number) |
    +------------+-------+---------------------+-------------+
    |       NULL | 山炮  |                   0 |        NULL |
    |          1 | 钢蛋  |                   2 |      119.00 |
    |          2 | 铁锤  |                   1 |      100.00 |
    +------------+-------+---------------------+-------------+
    3 rows in set (0.00 sec)

    4、查询姓“李”的老师的个数

    #使用正则表达式
    mysql> select * from teacher where tname regexp '^李';
    Empty set (0.00 sec)

    5、查询没学过“叶平”老师课的同学的学号、姓名

    分析:

    • 通过成绩表与学生表、课程表获取学生、课程以及教师id信息
    • 将上述查出的结果与教师表连表获取最终结果
    #获取学生、课程教师id信息
    mysql> select sc.student_id,st.sname,co.cname,co.teacher_id from score sc left j
    oin student st on st.sid = sc.student_id left join course co on co.cid = sc.cour
    se_id;
    +------------+-------+-------+------------+
    | student_id | sname | cname | teacher_id |
    +------------+-------+-------+------------+
    |          1 | 钢蛋  | 生物  |          1 |
    |          1 | 钢蛋  | 体育  |          1 |
    |          2 | 铁锤  | 体育  |          1 |
    +------------+-------+-------+------------+
    3 rows in set (0.00 sec)
    
    #获取最终结果
    mysql> select a.student_id,a.sname from (select sc.student_id,st.sname,co.cname,
    co.teacher_id from score sc left join student st on st.sid = sc.student_id left
    join course co on co.cid = sc.course_id) as a left join teacher te on a.teacher_
    id=te.tid where te.tname != '叶平';
    +------------+-------+
    | student_id | sname |
    +------------+-------+
    |          1 | 钢蛋  |
    |          1 | 钢蛋  |
    |          2 | 铁锤  |
    +------------+-------+
    3 rows in set (0.00 sec)

    6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名

    分析:

    • 先查出学习001课程所有的学生信息
    • 再查出学习002课程所有学生的信息
    • 上面查出的结果再作为查询结果集,查出符合条件的结果,条件就是这两个课程的学生id是一样的
    #所有学生的信息
    mysql> select st.sid,st.sname,co.cid,co.cname from score sc left join student st
    
        ->  on sc.student_id = st.sid left join course co on sc.course_id = co.cid;
    +------+-------+------+-------+
    | sid  | sname | cid  | cname |
    +------+-------+------+-------+
    |    1 | 钢蛋  |    1 | 生物  |
    |    1 | 钢蛋  |    2 | 体育  |
    |    2 | 铁锤  |    2 | 体育  |
    +------+-------+------+-------+
    3 rows in set (0.00 sec)
    
    #001课程学生信息
    mysql>  select b.sid,b.sname from
        ->  (select a.sid,a.sname,a.cid,a.cname from (select st.sid,st.sname,co.cid,co.cname from score sc left join student st
        ->  on sc.student_id = st.sid left join course co on sc.course_id = co.cid)as a where a.cid=2) as b;
    +------+-------+
    | sid  | sname |
    +------+-------+
    |    2 | 铁锤  |
    |    1 | 钢蛋  |
    +------+-------+
    2 rows in set (0.00 sec)
    
    #002课程学生信息
    mysql> select c.sid,c.sname from (select a.sid,a.sname,a.cid,a.cname from (select st.sid,st.sname,co.cid,co.cname from score sc left join student st
        ->  on sc.student_id = st.sid left join course co on sc.course_id = co.cid)
    as a where a.cid=1) as c;
    +------+-------+
    | sid  | sname |
    +------+-------+
    |    1 | 钢蛋  |
    +------+-------+
    1 row in set (0.00 sec)
    
    #利用同一个学生作为条件进行查询
    mysql>  select b.sid,b.sname from
        ->  (select a.sid,a.sname,a.cid,a.cname from (select st.sid,st.sname,co.cid,co.cname from score sc left join student st
        ->  on sc.student_id = st.sid left join course co on sc.course_id = co.cid)as a where a.cid=2) as b,
        ->
        -> (select a.sid,a.sname,a.cid,a.cname from (select st.sid,st.sname,co.cid,co.cname from score sc left join student st
        ->  on sc.student_id = st.sid left join course co on sc.course_id = co.cid)as a where a.cid=1) as c
        ->
        ->  where b.sid = c.sid;
    +------+-------+
    | sid  | sname |
    +------+-------+
    |    1 | 钢蛋  |
    +------+-------+
    1 row in set (0.00 sec)

    7、查询学过“叶平”老师所教的所有课的同学的学号、姓名

     分析:

    • 通过连表查出所有学生、教师、课程相关信息
    • 进行过滤
    #获取所有信息
    mysql> select st.sid,st.sname,te.tname,co.cname from score sc left join course c
    o on sc.course_id = co.cid left join teacher te on co.teacher_id = te.tid left j
    oin student st on sc.student_id = st.sid;
    +------+-------+-------+-------+
    | sid  | sname | tname | cname |
    +------+-------+-------+-------+
    |    1 | 钢蛋  | 波多  | 生物  |
    |    1 | 钢蛋  | 波多  | 体育  |
    |    2 | 铁锤  | 波多  | 体育  |
    +------+-------+-------+-------+
    3 rows in set (0.00 sec)
    
    #过滤获取符合要求的结果
    mysql> select st.sid,st.sname,te.tname,co.cname from score sc left join course c
    o on sc.course_id = co.cid left join teacher te on co.teacher_id = te.tid left j
    oin student st on sc.student_id = st.sid where te.tname='叶平';
    Empty set (0.00 sec)

    8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名

    分析:

    • 查出课程编号“002”成绩的所有同学信息
    • 查出课程编号“001”成绩的所有同学信息
    • 通过where语句进行筛选(条件是同一个同学、002成绩小于001成绩)
    #001成绩的同学信息
    mysql> select st.sid,st.sname,sc.number from score sc left join course co on sc.
    course_id = co.cid left join student st on sc.student_id = st.sid where co.cid=1
    ;
    +------+-------+--------+
    | sid  | sname | number |
    +------+-------+--------+
    |    1 | 钢蛋  |  60.00 |
    +------+-------+--------+
    1 row in set (0.00 sec)
    
    #002成绩的同学信息
    mysql> select st.sid,st.sname,sc.number from score sc left join course co on sc.
    course_id = co.cid left join student st on sc.student_id = st.sid where co.cid=2
    ;
    +------+-------+--------+
    | sid  | sname | number |
    +------+-------+--------+
    |    1 | 钢蛋  |  59.00 |
    |    2 | 铁锤  | 100.00 |
    +------+-------+--------+
    2 rows in set (0.00 sec)
    
    #过滤条件
    mysql> select a.sid,a.sname,a.number
        -> from
        -> (select st.sid,st.sname,sc.number from score sc left join course co on sc
    .
        -> course_id = co.cid left join student st on sc.student_id = st.sid where c
    o.cid=1) as a,
        ->
        -> (select st.sid,st.sname,sc.number from score sc left join course co on sc
    .
        -> course_id = co.cid left join student st on sc.student_id = st.sid where c
    o.cid=2) as b
        ->
        -> where a.sid = b.sid and a.number > b.number;
    +------+-------+--------+
    | sid  | sname | number |
    +------+-------+--------+
    |    1 | 钢蛋  |  60.00 |
    +------+-------+--------+
    1 row in set (0.00 sec)

    9、查询有课程成绩小于60分的同学的学号、姓名

    分析:

    • 通过连表获取所有同学的学号、姓名、课程、成绩信息
    • 通过where过滤出符合条件的信息
    #所有学生及成绩信息
    mysql> select st.sid,st.sname,co.cname,sc.number from score sc left join student
     st on sc.student_id = st.sid left join course co on sc. course_id = co.cid;
    +------+-------+-------+--------+
    | sid  | sname | cname | number |
    +------+-------+-------+--------+
    |    1 | 钢蛋  | 生物  |  60.00 |
    |    1 | 钢蛋  | 体育  |  59.00 |
    |    2 | 铁锤  | 体育  | 100.00 |
    +------+-------+-------+--------+
    3 rows in set (0.00 sec)
    
    #过滤
    mysql> select st.sid,st.sname,co.cname,sc.number from score sc left join student
     st on sc.student_id = st.sid left join course co on sc. course_id = co.cid wher
    e number < 60;
    +------+-------+-------+--------+
    | sid  | sname | cname | number |
    +------+-------+-------+--------+
    |    1 | 钢蛋  | 体育  |  59.00 |
    +------+-------+-------+--------+
    1 row in set (0.00 sec)

    10、查询没有学全所有课的同学的学号、姓名

    分析:

    • 通过课程表计算出所有课程的数目(count)
    • 计算出每一个同学(group by)所拥有的课程数量(count)
    • 将上述结果作为结果集使用where过滤
    #所有课程数量
    mysql> select count(co.cid) as co_count  from course co;
    +----------+
    | co_count |
    +----------+
    |        3 |
    +----------+
    1 row in set (0.00 sec)
    
    #每一个同学拥有的课程数量
    mysql> select st.sid,st.sname,count(co.cid) as st_co_count from score sc left jo
    in student st on sc.student_id = st.sid left join course co on sc.course_id = co
    .cid group by st.sid;
    +------+-------+-------------+
    | sid  | sname | st_co_count |
    +------+-------+-------------+
    |    1 | 钢蛋  |           2 |
    |    2 | 铁锤  |           1 |
    +------+-------+-------------+
    2 rows in set (0.00 sec)
    
    #进行过滤
    mysql> select a.sid,a.sname,a.st_co_count from (select st.sid,st.sname,count(co.
    cid) as st_co_count from score sc left join student st on sc.student_id = st.sid
     left join course co on sc.course_id = co.cid group by st.sid) as a,
        -> (select count(co.cid) as co_count  from course co) as b
        -> where a.st_co_count < b.co_count;
    +------+-------+-------------+
    | sid  | sname | st_co_count |
    +------+-------+-------------+
    |    1 | 钢蛋  |           2 |
    |    2 | 铁锤  |           1 |
    +------+-------+-------------+
    2 rows in set (0.00 sec)

    11、查询至少有一门课与学号为“001”的同学所学相同的同学的学号和姓名

    分析:

    • 查找“001”的同学的所有课程信息
    • 查找除“001”“同学以外的同学所有课程的信息
    • 通过课程名称进行过滤
    #所有同学的所有课程信息
    mysql> select st.sid,st.sname,co.cname from score sc left join student st on st.
    sid = sc.student_id left join course co on sc.course_id = co.cid;
    +------+-------+-------+
    | sid  | sname | cname |
    +------+-------+-------+
    |    1 | 钢蛋  | 生物  |
    |    1 | 钢蛋  | 体育  |
    |    2 | 铁锤  | 体育  |
    +------+-------+-------+
    3 rows in set (0.00 sec)
    
    #001同学课程的所有信息
    mysql> select st.sid,st.sname,co.cname from score sc left join student st on st.
    sid = sc.student_id left join course co on sc.course_id = co.cid where st.sid=1;
    
    +-----+-------+-------+
    | sid | sname | cname |
    +-----+-------+-------+
    |   1 | 钢蛋  | 生物  |
    |   1 | 钢蛋  | 体育  |
    +-----+-------+-------+
    2 rows in set (0.00 sec)
    
    #除001同学以外的同学课程信息
    mysql> select st.sid,st.sname,co.cname from score sc left join student st on st.
    sid = sc.student_id left join course co on sc.course_id = co.cid where st.sid !=
    1;
    +------+-------+-------+
    | sid  | sname | cname |
    +------+-------+-------+
    |    2 | 铁锤  | 体育  |
    +------+-------+-------+
    1 row in set (0.00 sec)
    
    #通过课程名字进行过滤
    mysql> select a.sid,a.sname,a.cname from
        -> (select st.sid,st.sname,co.cname from score sc left join student st on st
    .
        -> sid = sc.student_id left join course co on sc.course_id = co.cid where st
    .sid = 1) as a,
        -> (select st.sid,st.sname,co.cname from score sc left join student st on st
    .
        -> sid = sc.student_id left join course co on sc.course_id = co.cid where st
    .sid != 1) as b
        -> where b.cname regexp a.cname;
    +------+-------+-------+
    | sid  | sname | cname |
    +------+-------+-------+
    |    1 | 钢蛋  | 体育  |
    +------+-------+-------+
    1 row in set (0.00 sec)

    12、查询和“002”号的同学学习的课程完全相同的其他同学学号和姓名

    分析:

    这个和上面的差不多,只不过在最后的筛选条件处做一些改变

    mysql> select a.sid,a.sname,a.cname from
        -> (select st.sid,st.sname,co.cname from score sc left join student st on st
    .
        -> sid = sc.student_id left join course co on sc.course_id = co.cid where st
    .sid != 2) as a,
        -> (select st.sid,st.sname,co.cname from score sc left join student st on st
    .
        -> sid = sc.student_id left join course co on sc.course_id = co.cid where st
    .sid = 2) as b
        -> where b.cname = a.cname;
    +------+-------+-------+
    | sid  | sname | cname |
    +------+-------+-------+
    |    1 | 钢蛋  | 体育  |
    +------+-------+-------+
    1 row in set (0.00 sec)

    13、删除学习“叶平”老师课的SC表记录

     分析:

    • 先查找出叶平老师所教课程的所有cid
    • 根据课程cid删除对应的记录
    #叶平老师所教课程的cid
    mysql> select co.cid from course co left join teacher te on co.teacher_id=te.tid
     where te.tname='叶平';
    Empty set (0.00 sec)
    
    #根据cid删除记录
    mysql>  delete from score where course_id in (select co.cid from course co left
    join teacher te on co.teacher_id=te.tid where te.tname='叶平');
    Query OK, 0 rows affected (0.00 sec)

    ......待续

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  • 原文地址:https://www.cnblogs.com/shenjianping/p/11707660.html
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