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  • POJ 1318

    Word Amalgamation

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 4340    Accepted Submission(s): 2187


    Problem Description
    In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but in order to find the letters that appear in the answer it is necessary to unscramble four words. Your task is to write a program that can unscramble words.
     
    Input
    The input contains four parts:

    1. a dictionary, which consists of at least one and at most 100 words, one per line;
    2. a line containing XXXXXX, which signals the end of the dictionary;
    3. one or more scrambled `words' that you must unscramble, each on a line by itself; and
    4. another line containing XXXXXX, which signals the end of the file.

    All words, including both dictionary words and scrambled words, consist only of lowercase English letters and will be at least one and at most six characters long. (Note that the sentinel XXXXXX contains uppercase X's.) The dictionary is not necessarily in sorted order, but each word in the dictionary is unique.
     
    Output
    For each scrambled word in the input, output an alphabetical list of all dictionary words that can be formed by rearranging the letters in the scrambled word. Each word in this list must appear on a line by itself. If the list is empty (because no dictionary words can be formed), output the line ``NOT A VALID WORD" instead. In either case, output a line containing six asterisks to signal the end of the list.
     
    Sample Input
    tarp
    given
    score
    refund
    only
    trap
    work
    earn
    course
    pepper
    part
    XXXXXX
    resco
    nfudre
    aptr
    sett
    oresuc
    XXXXXX
     
    Sample Output
    score
    ******
    refund
    ******
    part
    tarp
    trap
    ******
    NOT A VALID WORD
    ******
    course
    ******
    先给定一个字典,再给一堆字符,每一串字符随机组合成字典中的单词,若可以组合成则单词字典序输出,否则输出无效的单词,每一个单词查找完后输出一行******
    容器+排序
    #include <iostream>
    #include <algorithm>
    #include <cstring>
    #include <cstdio>
    #include <vector>
    #include <queue>
    #include <cstdlib>
    #include <iomanip>
    #include <cmath>
    #include <ctime>
    #include <map>
    #include <set>
    using namespace std;
    #define lowbit(x) (x&(-x))
    #define max(x,y) (x>y?x:y)
    #define min(x,y) (x<y?x:y)
    #define MAX 100000000000000000
    #define MOD 1000000007
    #define pi acos(-1.0)
    #define ei exp(1)
    #define PI 3.141592653589793238462
    #define INF 0x3f3f3f3f3f
    #define mem(a) (memset(a,0,sizeof(a)))
    typedef long long ll;
    map<string,int>m;
    set<string>s[105];
    set<string>::iterator it;
    string str,rstr,name="XXXXXX";
    int main()
    {
        int tot=1;
        while(cin>>str)
        {
            if(str==name) break;
            rstr=str;
            sort(rstr.begin(),rstr.end());
            if(m[rstr]==0) m[rstr]=tot++;
            s[m[rstr]].insert(str);
        }
        while(cin>>str)
        {
            if(str==name)break;
            sort(str.begin(),str.end());
            if(m[str]==0) printf("NOT A VALID WORD
    ******
    ");
            else
            {
                for(it=s[m[str]].begin();it!=s[m[str]].end();it++)
                    cout<<*it<<endl;
                printf("******
    ");
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/shinianhuanniyijuhaojiubujian/p/7254044.html
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