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  • hibernate Restrictions用法

    方法

    说明

    Restrictions.eq

    Restrictions.allEq

    利用Map来进行多个等于的限制

    Restrictions.gt

    Restrictions.ge

    >=

    Restrictions.lt

    Restrictions.le

    <=

    Restrictions.between

    BETWEEN

    Restrictions.like

    LIKE

    Restrictions.in

    in

    Restrictions.and

    and

    Restrictions.or

    or

    Restrictions.sqlRestriction

    SQL限定查询

    QBC常用限定方法 

    Restrictions.eq --> equal,等于.

    Restrictions.allEq --> 参数为Map对象,使用key/value进行多个等于的比对,相当于多个Restrictions.eq 的效果

    Restrictions.gt --> great-than > 大于

    Restrictions.ge --> great-equal >= 大于等于

    Restrictions.lt --> less-than, < 小于

    Restrictions.le --> less-equal <= 小于等于

    Restrictions.between --> 对应SQLbetween子句

    Restrictions.like --> 对应SQLLIKE子句

    Restrictions.in --> 对应SQLin子句

    Restrictions.and --> and 关系

    Restrictions.or --> or 关系

    Restrictions.isNull --> 判断属性是否为空,为空则返回true

    Restrictions.isNotNull --> isNull相反

    Restrictions.sqlRestriction --> SQL限定的查询

    Order.asc --> 根据传入的字段进行升序排序

    Order.desc --> 根据传入的字段进行降序排序

    MatchMode.EXACT --> 字符串精确匹配.相当于"like 'value'"

    MatchMode.ANYWHERE --> 字符串在中间匹配.相当于"like '%value%'"

    MatchMode.START --> 字符串在最前面的位置.相当于"like 'value%'"

    MatchMode.END --> 字符串在最后面的位置.相当于"like '%value'"

    例子
    查询年龄在20-30岁之间的所有学生对象

    List list = session.createCriteria(Student.class).add(Restrictions.between("age",new Integer(20),new Integer(30)).list();

    查询学生姓名在AAA,BBB,CCC之间的学生对象

    String[] names = {"AAA","BBB","CCC"};
    List list = session.createCriteria(Student.class).add(Restrictions.in("name",names)).list();

    查询年龄为空的学生对象

    List list = session.createCriteria(Student.class).add(Restrictions.isNull("age")).list();

    查询年龄等于20或者年龄为空的学生对象

    List list = session.createCriteria(Student.class).add(Restrictions.or(Restrictions.eq("age",new Integer(20)),
    Restrictions.isNull("age")).list();

    --------------------------------------------------------------------
    使用QBC实现动态查询

    public List findStudents(String name,int age){
    
      Criteria criteria = session.createCriteria(Student.class);
      if(name != null){
         criteria.add(Restrictions.liek("name",name,MatchMode.ANYWHERE));
      }
      if(age != 0){
         criteria.add(Restrictions.eq("age",new Integer(age)));
      }
      criteria.addOrder(Order.asc("name"));//根据名字升序排列
      return criteria.list();
    }

    -----------------------------------------------------------------------------------

    今天用了写hibernate高级查询时用了Restrictions(当然Expression也是可以以的)这个类.感觉不错.
    下面的代码写的不易读.其实核心就是一句

    Restrictions.or(Restrictions.like(),Restrictions.or(Restrictions.like,........))

    里面的or可以无限加的.还是比较好用

            Session session = getHibernateTemplate().getSessionFactory().openSession();
            Criteria criteria = session.createCriteria(Film.class);
            List<Film> list = criteria.add(
                Restrictions.or(Restrictions.like("description", key,MatchMode.ANYWHERE),
                Restrictions.or(Restrictions.like("name", key,MatchMode.ANYWHERE),
                Restrictions.or(    Restrictions.like("direct", key,MatchMode.ANYWHERE),
                Restrictions.or(Restrictions.like("mainplay",key,MatchMode.ANYWHERE),
                Restrictions.like("filearea", key,MatchMode.ANYWHERE)))))).list();
         session.close();
            return list;    
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  • 原文地址:https://www.cnblogs.com/shuilangyizu/p/6018629.html
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