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  • C Primer Plus学习笔记 第10章 编程练习

    第一题

    #include <stdio.h>
    #define MONTHS 12
    #define YEARS 5
    
    int main(void)
    {
        const float rain[YEARS][MONTHS] =
        {
            {4.3, 4.3, 4.3, 3.0, 2.0, 1.2, 0.2, 0.2, 0.4, 2.4, 3.5, 6.6},
            {8.5, 8.2, 1.2, 1.6, 2.4, 0.0, 5.2, 0.9, 0.3, 0.9, 1.4, 7.3},
            {9.1, 8.5, 6.7, 4.3, 2.1, 0.8, 0.2, 0.2, 1.1, 2.3, 6.1, 8.4},
            {7.2, 9.9, 8.4, 3.3, 1.2, 0.8, 0.4, 0.0, 0.6, 1.7, 4.3, 6.2},
            {7.6, 5.6, 3.8, 2.8, 3.8, 0.2, 0.0, 0.0, 0.0, 1.3, 2.6, 5.2}
        };
        int year, month;
        float subtot, total;
    
        printf("YEAR    PAINFALL   (inches)
    ");
        for (year = 0, total = 0; year < YEARS; year++) {
            for (month = 0, subtot = 0; month < MONTHS; month++) {
                // 修改取值放hi是,用指针取值
                subtot += *(*(rain + year) + month);
            }
            printf("%5d %15.1f
    ", 2010 + year, subtot);
            total += subtot;
        }
        printf("
    The yearly average is %.1f inches.
    
    ", total / YEARS);
        printf("MONTHLY AVERAGES:
    
    ");
        printf(" Jan  Feb  Mar  Apr  May  Jun  Jul  Aug  Sep  Oct ");
        printf(" Nov  Dec
    ");
        
        for (month = 0; month < MONTHS; month++) {
            for (year = 0, subtot = 0; year < YEARS; year++) {
                // 修改取值放hi是,用指针取值
                subtot += *(*(rain + year) + month);
            }
            printf("%4.1f ",subtot / YEARS);    // 每个月的平均降水量
        }
        printf("
    ");
        
        return 0;
        
    }

    第二题

    #include <stdio.h>
    
    void copy_arr(double target1[], double source[], int n);
    void copy_ptr(double target2[], double source[], int n);
    void copy_ptrs(double [], double [], double * last);
    
    
    int main(void)
    {
        double source[5] ={1.1, 2.2, 3.3, 4.4, 5.5};
        double target1[5];
        double target2[5];
        double target3[5];
        
        copy_arr(target1, source, 5);
        copy_ptr(target2, source, 5);
        copy_ptrs(target3, source, source + 5);
        
    
        
        printf("source %p; target1 %p, target2 %p target3 %p.
    ", source, target1, target2, target3);
        printf("All index 1 is source %f; taeget1 %f; target2 %f target3 %f.
    ", *source, target1[0], *target2, target3[0]);
        
        return 0;
    }
    void copy_arr(double target1[], double source[], int n)
    {
        int i;
        for (i = 0; i < n; i++) {
            target1[i] = source [i];
        }
    }
    
    // 记住一点,C语言函数对任何一个传进来的参数,都会进行一次拷贝,这样就可以保证,函数不会改变外部的参数。
    void copy_ptr(double target2[], double source[], int n)
    {
        int i;
        for (i = 0; i < n; i++, source++) {
            *(target2 + i) = *source;
        }
    }
    
    void copy_ptrs(double target3[], double source[], double * last)
    {
        for (; source < last; target3++, source++) {
            *(target3) = *(source);
        }
        
    }

    输出

    source 0x7ffeefbff460; target1 0x7ffeefbff430, target2 0x7ffeefbff400 target3 0x7ffeefbff3d0.

    All index 1 is source 1.100000; taeget1 1.100000; target2 1.100000 target3 1.100000.

    第三题

    #include <stdio.h>
    #define MEMBER_NUMBER 5
    
    int max_number(int [], int);
    
    int main(void)
    {
        int ar[MEMBER_NUMBER] = {1, 9, 2, 4, 1};
        int number;
        number = max_number(ar, MEMBER_NUMBER);
        printf("The max number is %d.
    ", number);
        
        return 0;
    }
    
    int max_number(int ar[], int n)
    {
        int max_num , i;
        for (i = 0, max_num = ar[i]; i < n; i++) {
            max_num = (max_num > ar[i]) ? max_num : ar[i];
        }
        return max_num;
    }

    输出

    The max number is 9.

    Program ended with exit code: 0

    第四题

    #include <stdio.h>

    #define MEMBER_NUMBER 5

     

    int max_index(double [], int);

     

    int main(void)

    {

        double ar[MEMBER_NUMBER] = {1., 91.2, 12., 4., 11.12};

        int index;

        index = max_index(ar, MEMBER_NUMBER);

        printf("The max index is %d. ", index);

        

        return 0;

    }

     

    int max_index(double ar[], int n)

    {

        int i, index;

        double max_num;

        for (i = index = 0, max_num = ar[i]; i < n; i++) {

            if (ar[i] > max_num) {

                index = i;

                max_num = ar[i];

            }

        }

        return index;

    }

    输出

    The max index is 1.

    第五题

    #include <stdio.h>
    #define MEMBER_NUMBER 5
    
    double max_diff(double [], int);
    
    int main(void)
    {
        double ar[MEMBER_NUMBER] = {3.99, 9., 12., 4., 11.12};
        double res;
        res = max_diff(ar, MEMBER_NUMBER);
        printf("The max gap is %.2f.
    ", res);
        
        return 0;
    }
    
    double max_diff(double ar[], int n)
    {
        int i;
        double max_number, min_number;
        for (max_number = min_number = *ar, i = 0; i < n; i++) {
            max_number = (max_number > ar[i]) ? max_number : ar[i];
            min_number = (min_number < ar[i]) ? min_number : ar[i];
        }
        return max_number - min_number;
    }

    输出

    The max gap is 8.01.

    第六题

    #include <stdio.h>
    #define MEMBER_NUMBER 4
    
    void reveres(double [], int);
    
    void show(double ar[], int n);
    
    int main(void)
    {
        double ar[MEMBER_NUMBER] = {91.2, 12., 4., 11.12};
        reveres(ar, MEMBER_NUMBER);
        printf("The max index is .
    ");
        show(ar, MEMBER_NUMBER);
        return 0;
    }
    
    // 用一个临时变量接受
    void reveres(double ar[], int n)
    {
        int i;
        double temporary_number;
        for (i = 0; i < n / 2; i++) {
            temporary_number = ar[i];
            ar[i] = ar[n-i-1];
            ar[n-i-1] = temporary_number;
        }
    }
    
    void show(double ar[], int n)
    {
        int i;
        for (i = 0; i < n; i++) {
            printf("%f ", ar[i]);
        }
        printf("end.
    ");
    }

    第七题

    #include <stdio.h>
    
    void copy_arr(double target1[], double source[], int n);
    void copy_ptr(double target2[], double source[], int n);
    void copy_ptrs(double [], double [], double * last);
    
    
    int main(void)
    {
        double source[5] ={1.1, 2.2, 3.3, 4.4, 5.5};
        double target1[5];
        double target2[5];
        double target3[5];
        double source_two[2][3]= {1, 2, 3, 4, 5, 1};
        double target4[2][3];
        
        
        copy_arr(target1, source, 5);
        copy_ptr(target2, source, 5);
        copy_ptrs(target3, source, source + 5);
        // 分两次处理,第一次出来第一行,第二次处理第二行。
        copy_ptr(target4[0], source_two[0], 3);
        copy_ptr(target4[1], source_two[1], 3);
        printf("%f
    ", target4[1][2]);
    
        
        printf("source %p; target1 %p, target2 %p target3 %p.
    ", source, target1, target2, target3);
        printf("All index 1 is source %f; taeget1 %f; target2 %f target3 %f.
    ", *source, target1[0], *target2, target3[0]);
        
        return 0;
    }
    void copy_arr(double target1[], double source[], int n)
    {
        int i;
        for (i = 0; i < n; i++) {
            target1[i] = source [i];
        }
    }
    
    // 记住一点,C语言函数对任何一个传进来的参数,都会进行一次拷贝,这样就可以保证,函数不会改变外部的参数。
    void copy_ptr(double target2[], double source[], int n)
    {
        int i;
        for (i = 0; i < n; i++, source++) {
            *(target2 + i) = *source;
        }
    }
    
    void copy_ptrs(double target3[], double source[], double * last)
    {
        for (; source < last; target3++, source++) {
            *(target3) = *(source);
        }
        
    }

    第八题

     double source_7[7] = {1, 2, 3, 4, 5, 6, 7};
        double target_3[3];
        
        copy_arr(target_3, source_7+2, 3);
        printf("%f
    ", target_3[2]);

    复制了中间一小段代码

    第九题

    #include <stdio.h>
    #define ROWS 3
    #define COLUMNS 5
    
    void copy_arr(int r, int c, double soucre[r][c], double target[r][c]);
    void show_arr(int r, int c, double soucre[r][c], double target[r][c]);
    int main(void)
    {
        int row = 3, col = 5;
        double s_arr[ROWS][COLUMNS] = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15};
        double t_arr[row][col];
        copy_arr(row, col, s_arr, t_arr);
        show_arr(row, col, s_arr, t_arr);
        return 0;
    }
    
    // 拷贝数组
    void copy_arr(int r, int c, double soucre[r][c], double target[r][c])
    {
        int nr, nc;
        for (nr = 0; nr < r; nr++) {
            for (nc = 0; nc < c; nc++) {
                target[nr][nc] = soucre[nr][nc];
            }
        }
    }
    
    // 显式数组
    void show_arr(int r, int c, double soucre[r][c], double target[r][c])
    {
        int nr, nc;
        for (nr = 0; nr < r; nr++) {
            for (nc = 0; nc < c; nc++) {
                printf("%f ", soucre[nr][nc]);
            }
        }
        putchar('
    ');
        for (nr = 0; nr < r; nr++) {
            for (nc = 0; nc < c; nc++) {
                printf("%f ", target[nr][nc]);
            }
        }
        putchar('
    ');
        
    }

    第十题

    #include <stdio.h>
    #define COUNT 4
    
    void sum_arr(int add1[], int add2[], int res[], int n);
    void show(int ar[], int n);
    
    int main(void)
    {
        int ar1[COUNT] = {1, 2, 3, 4};
        int ar2[COUNT] = {4, 3, 2, 1};
        int res[COUNT];
        
        sum_arr(ar1, ar2, res, COUNT);
        show(res, COUNT);
        
        return 0;
        
    }
    
    void sum_arr(int add1[], int add2[], int res[], int n)
    {
        int i;
        for (i = 0; i < n; i++) {
            res[i] = add1[i] + add2[i];
        }
        
    }
    
    
    void show(int ar[], int n)
    {
        int i;
        for (i = 0; i < n; i++) {
            printf("%d ", ar[i]);
        }
        printf("
    *** end *** 
    ");
    }

    第十一题

    #include <stdio.h>
    #define ROWS 3
    #define COLUMNS 5
    
    
    void arr_double(int ar[][COLUMNS], int n);
    void show(int ar[][COLUMNS], int n);
    
    int main(void)
    {
        int ar[ROWS][COLUMNS] = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15};
        show(ar, ROWS);
        arr_double(ar, ROWS);
        show(ar, ROWS);
        
        return 0;
        
    }
    
    // 原数值翻倍
    void arr_double(int ar[][COLUMNS], int n)
    {
        int r, c;
        for (r = 0; r < n; r++) {
            for (c = 0; c < COLUMNS; c++) {
                ar[r][c] *= 2;
            }
        }
    }
    
    
    // 显式数值
    void show(int ar[][COLUMNS], int n)
    {
        int r, c;
        for (r = 0; r < n; r++) {
            for (c = 0; c < COLUMNS; c++) {
                printf("%d ", ar[r][c]);
            }
            printf("
    ");
        }
        printf("
    *** end *** 
    ");
    }

    第十二题

    #include <stdio.h>
    #define MONTHS 12
    #define YEARS 5
    
    void show_year_info(const double rain[][MONTHS], int row);
    void show_month_info(const double rain[][MONTHS], int row);
    
    int main(void)
    {
        const double rain[YEARS][MONTHS] =
        {
            {4.3, 4.3, 4.3, 3.0, 2.0, 1.2, 0.2, 0.2, 0.4, 2.4, 3.5, 6.6},
            {8.5, 8.2, 1.2, 1.6, 2.4, 0.0, 5.2, 0.9, 0.3, 0.9, 1.4, 7.3},
            {9.1, 8.5, 6.7, 4.3, 2.1, 0.8, 0.2, 0.2, 1.1, 2.3, 6.1, 8.4},
            {7.2, 9.9, 8.4, 3.3, 1.2, 0.8, 0.4, 0.0, 0.6, 1.7, 4.3, 6.2},
            {7.6, 5.6, 3.8, 2.8, 3.8, 0.2, 0.0, 0.0, 0.0, 1.3, 2.6, 5.2}
        };
        
        show_year_info(rain, YEARS);
        show_month_info(rain, YEARS);
        
        
        return 0;
        
    }
    
    // 记得函数定义const,因为传入的指针就定义了const
    void show_year_info(const double rain[][MONTHS], int row)
    {
        float subtot, total;
        int year, month;
        printf("YEAR    PAINFALL   (inches)
    ");
        for (year = 0, total = 0; year < row; year++) {
            for (month = 0, subtot = 0; month < MONTHS; month++) {
                subtot += rain[year][month];
            }
            printf("%5d %15.1f
    ", 2010 + year, subtot);
            total += subtot;
        }
        printf("
    The yearly average is %.1f inches.
    
    ", total / YEARS);
    }
    
    
    void show_month_info(const double rain[][MONTHS], int row)
    {
        float subtot;
        int year, month;
        printf("MONTHLY AVERAGES:
    
    ");
        printf(" Jan  Feb  Mar  Apr  May  Jun  Jul  Aug  Sep  Oct ");
        printf(" Nov  Dec
    ");
        
        for (month = 0; month < MONTHS; month++) {
            for (year = 0, subtot = 0; year < row; year++) {
                subtot += rain[year][month];
            }
            printf("%4.1f ",subtot / YEARS);    // 每个月的平均降水量
        }
        printf("
    ");
    }

    第十三题

    #include <stdio.h>
    #define ROWS 3
    #define COLUMNS 5
    
    void scanf_elemet(double ar[][COLUMNS], int row);
    double average_serier(const double ar[], int columns);
    double average_all(double ar[][COLUMNS], int row);
    double max_number(double ar[][COLUMNS], int row);
    void show(double ar[][COLUMNS], int n);
    
    int main(void)
    {
        int i;
        
        double ar[ROWS][COLUMNS];
        scanf_elemet(ar, ROWS);
        for (i = 0; i < ROWS; i++) {
            average_serier(ar[i], COLUMNS);
        }
        average_all(ar, ROWS);
        max_number(ar, ROWS);
        show(ar, ROWS);
        
        return 0;
    }
    
    //找出最大值
    double max_number(double ar[][COLUMNS], int row)
    {
        int r, c;
        double max_num;
        for (r = 0, max_num = **ar; r < row; r++) {
            for (c = 0; c < COLUMNS; c++) {
                max_num = (max_num > ar[r][c]) ? max_num : ar[r][c];
            }
        }
        printf("The max number is %g.
    ", max_num);
        
        return max_num;
        
    }
    
    /* 计算所有值的平均值 */
    double average_all(double ar[][COLUMNS], int row)
    {
        int r, c;
        double total, aver_num;
        for (r = 0, total = 0; r < row; r++) {
            for (c = 0; c < COLUMNS; c++) {
                total += ar[r][c];
            }
        }
        
        aver_num = total / (row * COLUMNS);
        printf("All average is %g.
    ", aver_num);
        
        return aver_num;
    }
    
    
    // 计算以为数组的平均值,调用三次
    double average_serier(const double ar[], int colums)
    {
        int i;
        double total, aver_num;
        for (i = 0, total = 0; i < colums; i++) {
            total += ar[i];
        }
        
        aver_num = total / colums;
        printf("average is %g.
    ", aver_num);
        
        return aver_num;
    }
    
    // 接受15个数组的输入
    void scanf_elemet(double ar[][COLUMNS], int row)
    {
        
        int r, c;
        
        for (r = 0; r < row; r ++) {
            printf("Please enter the %d float number:
    ", COLUMNS);
            for (c = 0; c < COLUMNS; c++) {
                scanf("%lf", &ar[r][c]);
            }
        }
    }
    
    
    void show(double ar[][COLUMNS], int n)
    {
        int r, c;
        for (r = 0; r < n; r++) {
            for (c = 0; c < COLUMNS; c++) {
                printf("%g ", ar[r][c]);
            }
            printf("
    ");
        }
        printf("
    *** end *** 
    ");
    }

    第十四题

    #include <stdio.h>
    #define ROWS 3
    #define COLUMNS 5
    
    void scanf_elemet(int row, int column,double ar[row][column]);
    double average_serier(const double ar[], int columns);
    double average_all(int row, int column,double ar[row][column]);
    double max_number(int row, int column,double ar[row][column]);
    void show(int row, int column,double ar[row][column]);
    
    int main(void)
    {
        int i;
        
        double ar[ROWS][COLUMNS];
        scanf_elemet(ROWS, COLUMNS, ar);
        for (i = 0; i < ROWS; i++) {
            average_serier(ar[i], COLUMNS);
        }
        average_all(ROWS, COLUMNS, ar);
        max_number(ROWS, COLUMNS, ar);
        show(ROWS, COLUMNS, ar);
        
        return 0;
    }
    
    //找出最大值
    double max_number(int row, int column,double ar[row][column])
    {
        int r, c;
        double max_num;
        for (r = 0, max_num = **ar; r < row; r++) {
            for (c = 0; c < column; c++) {
                max_num = (max_num > ar[r][c]) ? max_num : ar[r][c];
            }
        }
        printf("The max number is %g.
    ", max_num);
        
        return max_num;
        
    }
    
    /* 计算所有值的平均值 */
    double average_all(int row, int column,double ar[row][column])
    {
        int r, c;
        double total, aver_num;
        for (r = 0, total = 0; r < row; r++) {
            for (c = 0; c < column; c++) {
                total += ar[r][c];
            }
        }
        
        aver_num = total / (row * COLUMNS);
        printf("All average is %g.
    ", aver_num);
        
        return aver_num;
    }
    
    
    // 计算以为数组的平均值,调用三次
    double average_serier(const double ar[], int colums)
    {
        int i;
        double total, aver_num;
        for (i = 0, total = 0; i < colums; i++) {
            total += ar[i];
        }
        
        aver_num = total / colums;
        printf("average is %g.
    ", aver_num);
        
        return aver_num;
    }
    
    // 接受15个数组的输入
    void scanf_elemet(int row, int column,double ar[row][column])
    {
        
        int r, c;
        
        for (r = 0; r < row; r ++) {
            printf("Please enter the %d float number:
    ", COLUMNS);
            for (c = 0; c < column; c++) {
                scanf("%lf", &ar[r][c]);
            }
        }
    }
    
    
    void show(int row, int column,double ar[row][column])
    {
        int r, c;
        for (r = 0; r < row; r++) {
            for (c = 0; c < column; c++) {
                printf("%g ", ar[r][c]);
            }
            printf("
    ");
        }
        printf("
    *** end *** 
    ");
    }
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  • 原文地址:https://www.cnblogs.com/sidianok/p/14259679.html
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