题目链接
https://leetcode.com/problems/path-sum/
题目原文
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:
Given the below binary tree and sum = 22,
return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
题目大意
给出一棵树和一个整数,是否可以找到一条根到叶子的路径,使得路径上所有节点的和等于该整数
解题思路
递归求解
代码
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def hasPathSum(self, root, sum):
"""
:type root: TreeNode
:type sum: int
:rtype: bool
"""
if root == None:
return False
if root.left == None and root.right == None:
return root.val == sum
return self.hasPathSum(root.left, sum - root.val) or self.hasPathSum(root.right, sum - root.val)