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  • day12作业答案

    2.1
    # lst=['asdgg','as','drtysr']
    # lst2=[i.upper()  for i in lst if len(i) >3 ]
    # print(lst2)
    # 2.2
    # tu=[(x,y) for x in range(6) if x%2==0 for y in range(6) if y%2==0]
    # print(tu)
    # 
    # 2.3
    # M=[[1,2,3],[4,5,6],[7,8,9]]
    # a=[i[2] for i in M]
    # print(a)
    # 
    # 2.4
    # a=[i**2 for i in range(50 ) if i %3==0]
    # print(a)
    # 
    # 2.5
    # a=['python%s期' % i for i in range(1,11)]
    # print(a)
    # 
    # 2.6
    # a=[(i,i+1) for i in range(6)]
    # print(a)
    # 
    # 2.7
    # a=[i for i in range(0,20,2)]
    # print(a)
    # 
    # 2.8
    # l1=['alex','wusir','老男孩','太白']
    # a=[(l1[i]+str(i)) for i in range(4)]
    # print(a)
    # 
    # 2.9
    # x={
    #     'name':'alex',
    #     'values':[{'timestamp':1517991992.94,'values':100},
    #               {'timestamp':1517992000.94,'values':300},
    #               {'timestamp':1517992014.94,'values':300},
    #               {'timestamp': 1517992744.94, 'values': 350},
    #               {'timestamp': 1517992800.94, 'values': 280},
    # 
    #               ]}
    # a=[[i['timestamp'],i['values']] for i in x['values']]
    # print(a)
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  • 原文地址:https://www.cnblogs.com/snackpython/p/9979498.html
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