杭电2055--An easy problme

An easy problem

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 16646    Accepted Submission(s): 
11183

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

 

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

 

Output

for each case, you should the result of y+f(x) on a line.

 

Sample Input

6

R 1

P 2

G 3

r 1

p 2

g 3

 

Sample Output

19

18

10

-17

-14

-4

 

Author

8600

 

Source

校庆杯Warm Up

 

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//AC:

#include <stdio.h>

int deal(char str)
{
    if(str>='A' , str<='Z')
    return str - 'A' + 1 ;
    else
    return 'a' - str - 1 ;
}

void math()
{
    int num; char str ;
    scanf("%s %d", &str, &num) ;
    int temp = deal(str) ;
    printf("%d
", temp + num) ;
}

int main()
{
    int t ;
    scanf("%d", &t) ;
    while(t--)
    {
        math() ;
    }    
    return 0 ;
}