杭电1012--u Calculate e

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 35178    Accepted Submission(s): 15843

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

n e 
- ----------- 
0 1 
1 2 
2 2.5 
3 2.666666667 
4 2.708333333

 

Source

Greater New York 2000

 

//水题，格式； 

#include<stdio.h>
double sieve[100];
int main()
{
    int i, total=1; sieve[0]=1;
    for(i=1;i<10;i++)
    {
        total*=i;
        sieve[i]=sieve[i-1]+1.0/total;    
    }
    printf("n e
");
    printf("- -----------
");
    int n;
    for(i=0;i<10;i++)
    {
        printf("%d ",i);
        if(i<=1)
        printf("%d
",(int)sieve[i]);
        else if(i==2)
        printf("%.1lf
",sieve[i]);
        else
        printf("%.9lf
",sieve[i]);
    }
    return 0;
}