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  • 杭电2120--Ice_cream's world I(并查集)

    Ice_cream's world I

    Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 758    Accepted Submission(s): 442


    Problem Description
    ice_cream's world is a rich country, it has many fertile lands. Today, the queen of ice_cream wants award land to diligent ACMers. So there are some watchtowers are set up, and wall between watchtowers be build, in order to partition the ice_cream’s world. But how many ACMers at most can be awarded by the queen is a big problem. One wall-surrounded land must be given to only one ACMer and no walls are crossed, if you can help the queen solve this problem, you will be get a land.
     

     

    Input
    In the case, first two integers N, M (N<=1000, M<=10000) is represent the number of watchtower and the number of wall. The watchtower numbered from 0 to N-1. Next following M lines, every line contain two integers A, B mean between A and B has a wall(A and B are distinct). Terminate by end of file.
     

     

    Output
    Output the maximum number of ACMers who will be awarded.
    One answer one line.
     

     

    Sample Input
    8 10
    0 1
    1 2
    1 3
    2 4
    3 4
    0 5
    5 6
    6 7
    3 6
    4 7
     

     

    Sample Output
    3
     

     

    Author
    Wiskey
     

     

    Source
     

     

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    //计算成环个数;
     1 #include <stdio.h>
     2 int father[1010];
     3 int find(int a)
     4 {
     5     while(a != father[a])
     6     a = father[a];
     7     return a;
     8 }
     9 void mercy(int a, int b)
    10 {
    11     int q = find(a);
    12     int p = find(b);
    13     if(q != p)
    14     father[q] = p;
    15 }
    16 int main()
    17 {
    18     int i, n, m;
    19     while(~scanf("%d %d", &n, &m))
    20     {
    21         int total = 0;
    22         for(i=0; i<n; i++)
    23         father[i] = i;
    24         for(i=0; i<m; i++)
    25         {
    26             int a, b;
    27             scanf("%d %d", &a, &b);
    28             if(find(a) == find(b))
    29             {
    30                 //printf("
      %d %d
    ", a, b);
    31                 total++;
    32             }
    33             else
    34             mercy(a, b);
    35         }
    36         printf("%d
    ", total);
    37     }
    38 }
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  • 原文地址:https://www.cnblogs.com/soTired/p/4680340.html
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