python 判断号码是否可用(号码过滤)

def delCustomer(customer):  # 返回两个 第一个用来标记是否可用，第二个标记号码
    f = open(AbnormalPhone,"r")
    src = f.readlines()
    f.close()
    abnormalSet = set()
    for line in src:
        phone = str(line.split("
")[0].strip())
        abnormalSet.add(phone)

    matchObj = re.match('0?1[3-9]d{9}$', customer)
    if (matchObj!=None): # 如果是手机号
        if len(customer) == 11: 
            return 1,customer
        elif len(customer) == 12: 
            return 1,customer[1:]
    else: #如果不是手机号
        matchObj = re.match('0(10|2d)', customer) # 区号是3位 customer[0:3], customer[3:]  区号，号码
        if (matchObj != None):
            if (len(customer[3:]) == 7 or len(customer[3:]) == 8) and customer not in abnormalSet:
                return 1,customer
            else:
                return 0,customer

        matchObj = re.match('0([3-9]d{2})', customer) # 区号是4位  customer[0:4], customer[4:]  区号，号码
        if (matchObj != None):
            if (len(customer[4:]) == 7 or len(customer[4:]) == 8) and customer not in abnormalSet:
                return 1,customer
            else:
                return 0, customer

        if (len(customer) == 7 or len(customer) == 8) and customer not in abnormalSet:
            return 1,customer
        else:
            return 0,customer