题意:为每个小伙伴切糕,要求每个小盆友(包括你自己)分得的pie一样大,但是每个人只能分得一份pie,不能拿两份凑一起的。
做法:二分查找切糕的大小,然后看看分出来的个数有没有大于小盆友们的个数,它又没说每个pie都要分完,分不完的留给工作人员吃嘛。
代码:
/* * Author: illuz <iilluzen[at]gmail.com> * Blog: http://blog.csdn.net/hcbbt * File: live3652.cpp * Create Date: 2013-09-10 00:40:36 * Descripton: binary, greedy */ #include <cstdio> #include <cmath> #include <cstdlib> #include <algorithm> using namespace std; const int MAXN = 10010; const double PI = acos(-1.0); int n, f, t; double a[MAXN], Max; bool judge(double x) { int sum = 0; for (int i = 0; i < n; i++) sum += a[i] / x; if (sum >= f + 1) return true; return false; } int main() { scanf("%d", &t); while (t--) { scanf("%d%d", &n, &f); for (int i = 0; i < n; i++) { scanf("%lf", &a[i]); a[i] = PI * a[i] * a[i]; Max = max(Max, a[i]); } double low = 0, mid; while (Max - low > 1e-5) { mid = low + (Max - low) / 2; if (judge(mid)) low = mid; else Max = mid; } printf("%.4lf ", low); } return 0; }