Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
For example,
If n = 4 and k = 2, a solution is:
[ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ]
思路: 回溯法 剪枝叶
public class Solution { public List<List<Integer>> combine(int n, int k) { List<List<Integer>> result = new ArrayList<List<Integer>>(); if(n == 0 || k == 0 || n < k) { return result; } List<Integer> list = new ArrayList<Integer>(); helper(result, list, 1, n, k); return result; } public void helper(List<List<Integer>> result, List<Integer> list, int i, int n , int k) { if(list.size() == k) { result.add(new ArrayList<Integer>(list)); return; } for(int j = i; j <= n; j++) { list.add(j); helper(result, list,j + 1, n, k); list.remove(list.size() - 1); } } }