Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:
Given the below binary tree and sum = 22,
5
/
4 8
/ /
11 13 4
/ /
7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void sub(vector<vector<int> >& ret,vector<int>& val,TreeNode *root,int sum){
// Start typing your C/C++ solution below
// DO NOT write int main() function
if(root==NULL)return;
if(root->left==NULL&&root->right==NULL){
//leaf
if(root->val==sum){
val.push_back(root->val);
ret.push_back(val);
val.pop_back();
}
else return;
}
else{
val.push_back(root->val);
sub(ret,val,root->left,sum-root->val);
sub(ret,val,root->right,sum-root->val);
val.pop_back();
}
}
vector<vector<int> > pathSum(TreeNode *root, int sum) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
vector<vector<int> > ret;
vector<int> val;
sub(ret,val,root,sum);
return ret;
}
};