第四题：进行输出打印
1 #include <stdio.h> 2 3 void main() 4 { 5 printf("*****************************\n"); 6 printf("\tVery good!\t\t\n"); 7 printf("*****************************\n"); 8 }
第五题：输入a，b，c三个值，输出其中最大者。
1 #include <stdio.h> 2 3 void main() 4 { 5 int max(int x,int y); //函数的声明 6 int a,b,c; 7 scanf("%d,%d,%d",&a,&b,&c); //获得输入 8 printf("%d",max(a,max(b,c))); 9 } 10 11 int max(int x,int y) 12 { 13 return ( x>y ? x : y ); 14 }
===========================2012-5-11=============================
1 ; int __cdecl main(int argc, const char **argv, const char **envp) 2 _main proc near 3 4 var_C= dword ptr -0Ch 5 var_8= dword ptr -8 6 var_4= dword ptr -4 7 argc= dword ptr 4 8 argv= dword ptr 8 9 envp= dword ptr 0Ch 10 11 sub esp, 0Ch 12 lea eax, [esp+0Ch+var_C] 13 lea ecx, [esp+0Ch+var_8] 14 lea edx, [esp+0Ch+var_4] 15 push eax 16 push ecx 17 push edx 18 push offset Format ; "%d,%d,%d" 19 call _scanf 20 mov eax, [esp+1Ch+var_C] 21 mov ecx, [esp+1Ch+var_8] 22 push eax 23 push ecx 24 call sub_401050 25 mov edx, [esp+24h+var_4] 26 push eax 27 push edx 28 call sub_401050 29 push eax 30 push offset aD ; "%d \n" 31 call _printf 32 add esp, 34h 33 retn 34 _main endp
修改为：
1 ; int __cdecl main(int argc, const char **argv, const char **envp) 2 _main proc near 3 4 c= dword ptr -0Ch 5 b= dword ptr -8 6 a= dword ptr -4 7 argc= dword ptr 4 8 argv= dword ptr 8 9 envp= dword ptr 0Ch 10 11 sub esp, 0Ch 12 lea eax, [esp+0Ch+c] 13 lea ecx, [esp+0Ch+b] 14 lea edx, [esp+0Ch+a] 15 push eax 16 push ecx 17 push edx 18 push offset Format ; "%d,%d,%d" 19 call _scanf 20 mov eax, [esp+1Ch+c] 21 mov ecx, [esp+1Ch+b] 22 push eax 23 push ecx 24 call func_max 25 mov edx, [esp+24h+a] 26 push eax 27 push edx 28 call func_max 29 push eax 30 push offset aD ; "%d \n" 31 call _printf 32 add esp, 34h 33 retn 34 _main endp
这样一来，我们就很容易的看到，程序首先调用了max函数比较b和c的大小，如何再和a比较。