通过UIButton的tag进行传参

在给UIbutton绑定target嘚时候会遇到传递参数的问题，但默认的参数是一个(id)sender

- (void)noteBtnClicked:(id)sender {
}

　　其实就是UIButton自身，也就只能利用UIButton自身的属性进行传值，貌似也只有这一个tag可以办到

于是可以这样：

-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    
    HomeVideoCell *cell = (HomeVideoCell *)[tableView dequeueReusableCellWithIdentifier:@"HomeVideoCell"];
    cell.selectionStyle = UITableViewCellSelectionStyleNone;
    
    
    NewsListModel *model = [self.contentArray objectAtIndex:indexPath.row];
    [cell setVideoCellWithModel:model];
    
    
    cell.storeBtn.tag = [model.tId integerValue];
    [cell.storeBtn addTarget:self action:@selector(storeBtnClicked:) forControlEvents:UIControlEventTouchUpInside];
    [cell.shareBtn addTarget:self action:@selector(shareBtnClicked:) forControlEvents:UIControlEventTouchUpInside];
    [cell.noteBtn addTarget:self action:@selector(noteBtnClicked:) forControlEvents:UIControlEventTouchUpInside];
    
    
    return cell;
}

利用

cell.storeBtn.tag = [model.tId integerValue];存储在tag上；
在相应方法里面就可以通过传入的button拿到tag

//收藏
- (void)storeBtnClicked:(UIButton *)sender {
    
    NSString *value = [NSString stringWithFormat:@"%ld",(long)sender.tag];
}