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  • oracle分区表之列表分区

    SQL> -- Create test table
    SQL> drop table list_partition_test;
    Table dropped
    SQL> create table list_partition_test
      2  (
      3    empno    NUMBER(4),
      4    ename    VARCHAR2(10),
      5    job      VARCHAR2(9),
      6    mgr      NUMBER(4),
      7    hiredate DATE,
      8    sal      NUMBER(7,2),
      9    comm     NUMBER(7,2),
     10    deptno   NUMBER(2),
     11    dt       VARCHAR2(20)
     12  )
     13  partition by list (DT)
     14  (
     15    partition DT_PARTITION values ('20180512', '20180513', '20180514', '20180515')
     16  );
    Table created
    SQL> --添加数据
    SQL> begin
      2    for i in 20180512..20180515 loop
      3    insert into list_partition_test select t.*,i from scott.emp t;
      4    end loop;
      5  end;
      6  /
    PL/SQL procedure successfully completed
    SQL> --用分区字段筛选查询
    SQL> select *
      2    from list_partition_test
      3   where dt = '20180515';
    EMPNO ENAME      JOB         MGR HIREDATE          SAL      COMM DEPTNO DT
    ----- ---------- --------- ----- ----------- --------- --------- ------ --------------------
     7369 SMITH      CLERK      7902 1980/12/17     800.00               20 20180515
     7499 ALLEN      SALESMAN   7698 1981/2/20     1600.00    300.00     30 20180515
     7521 WARD       SALESMAN   7698 1981/2/22     1250.00    500.00     30 20180515
     7566 JONES      MANAGER    7839 1981/4/2      2975.00               20 20180515
     7654 MARTIN     SALESMAN   7698 1981/9/28     1250.00   1400.00     30 20180515
     7698 BLAKE      MANAGER    7839 1981/5/1      2850.00               30 20180515
     7782 CLARK      MANAGER    7839 1981/6/9      2450.00               10 20180515
     7788 SCOTT      ANALYST    7566 1987/4/19     3000.00               20 20180515
     7839 KING       PRESIDENT       1981/11/17    5000.00               10 20180515
     7844 TURNER     SALESMAN   7698 1981/9/8      1500.00      0.00     30 20180515
     7876 ADAMS      CLERK      7788 1987/5/23     1100.00               20 20180515
     7900 JAMES      CLERK      7698 1981/12/3      950.00               30 20180515
     7902 FORD       ANALYST    7566 1981/12/3     3000.00               20 20180515
     7934 MILLER     CLERK      7782 1982/1/23     1300.00               10 20180515
    14 rows selected
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  • 原文地址:https://www.cnblogs.com/wangzihong/p/9029319.html
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