Go复习之坑-遍历取地址和值

package main

import "fmt"

type student struct {
    name string
    age int
}

func main() {
    students := []student{{"wjc",33},{"kelvin",11}}
    stuMap := make(map[int]*student)
    for i,stu := range students{
        stuMap[i] = &stu
        fmt.Printf("%p,%+v
",&stu,stu)
    }

    for k,v := range stuMap{
        fmt.Println(k,v)
    }

    for i,_:= range students{
        stuMap[i] = &students[i]
        fmt.Printf("%p,%+v
",&students[i],students[i])
    }

    for k,v := range stuMap{
        fmt.Println(k,v)
    }
}

//输出

0xc00005a440,{name:wjc age:33}
0xc00005a440,{name:kelvin age:11}
0 &{kelvin 11}
1 &{kelvin 11}
0xc00006a330,{name:wjc age:33}
0xc00006a348,{name:kelvin age:11}
0 &{wjc 33}
1 &{kelvin 11}

坑总结：

 循环过程中，stu变量只声明了一次，所以stu地址即&stu是不变的，值是变化的。所以&stu始终不变