P2290 [HNOI2004]树的计数
prufer序列模板题
#include <iostream> #include <cstdio> #include <queue> #include <algorithm> #include <cmath> #include <cstring> #define inf 2147483647 #define N 1000010 #define p(a) putchar(a) #define For(i,a,b) for(long long i=a;i<=b;++i) //by war //2019.8.26 using namespace std; long long n,sum,flag,cnt,temp,ans; long long a[N],prime[N],tot[N]; bool vis[N]; void in(long long &x){ long long y=1;char c=getchar();x=0; while(c<'0'||c>'9'){if(c=='-')y=-1;c=getchar();} while(c<='9'&&c>='0'){ x=(x<<1)+(x<<3)+c-'0';c=getchar();} x*=y; } void o(long long x){ if(x<0){p('-');x=-x;} if(x>9)o(x/10); p(x%10+'0'); } void Euler(){ for(long long i=2;i<=150;i++){ if(!vis[i]) prime[++cnt]=i; for(long long j=1;j<=cnt&&i*prime[j]<=150;j++){ vis[i*prime[j]]=1; if(i%prime[j]==0) break; } } } long long ksm(long long a,long long b){ long long r=1; while(b>0){ if(b&1) r*=a; a*=a; b>>=1; } return r; } signed main(){ in(n);Euler(); For(i,1,n){ in(a[i]),sum+=a[i]-1; if(!a[i]) flag=1; } if(n==1&&flag){ o(1); return 0; } if(sum!=n-2||flag){ o(0); return 0; } For(i,2,n-2){ temp=i; For(j,1,cnt) while(temp%prime[j]==0){ tot[prime[j]]++; temp/=prime[j]; } } For(i,1,n) For(j,2,a[i]-1){ temp=j; For(k,1,cnt) while(temp%prime[k]==0){ tot[prime[k]]--; temp/=prime[k]; } } ans=1; For(i,1,cnt) ans*=ksm(prime[i],tot[prime[i]]); o(ans); return 0; }