HDOJ(HDU) 2123 An easy problem(简单题...)

Problem Description
In this problem you need to make a multiply table of N * N ,just like the sample out. The element in the ith row and jth column should be the product(乘积) of i and j.

Input
The first line of input is an integer C which indicate the number of test cases.

Then C test cases follow.Each test case contains an integer N (1<=N<=9) in a line which mentioned above.

Output
For each test case, print out the multiply table.

Sample Input
2
1
4

Sample Output
1
1 2 3 4
2 4 6 8
3 6 9 12
4 8 12 16

就是输入t个数，对于每个数n，输出n*n个数。
i为1-n，j为1-n，输出i*j。
每一行最后一个输出后面没有空格啊！！！

import java.util.Scanner;

public class Main{

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t =sc.nextInt();
        while(t-->0){
            int n =sc.nextInt();
            for(int i=1;i<=n;i++){
                for(int j=1;j<=n;j++){
                    if(j==1){
                        System.out.print(i*j);
                    }else{
                        System.out.print(" "+i*j);
                    }
                }
                System.out.println();
            }
        }
    }
}