zoukankan      html  css  js  c++  java
  • javascript A*算法 寻路算法 获取最短路径算法

      1 //A算法 自动寻路 路径
      2 class GetAutoPath{
      3 
      4     constructor(id, map, sPos, ePos, mapArr){
      5         //this.type = id.type;
      6         this.id = id;
      7         this.map = map;
      8         this.sPos = sPos;
      9         this.ePos = ePos;
     10         this.mapArr = mapArr;
     11         this.maxMach = 10000;
     12         this.openArr = [];
     13         this.closeArr = [];
     14         this.minPath = [];
     15         if(!this.isPath(this.sPos.x, this.sPos.y)){this.sPos = this.getNewDot(sPos, ePos);}
     16         if(!this.isPath(this.ePos.x, this.ePos.y)){this.ePos = this.getNewDot(ePos, sPos);}
     17         //console.log(this.mapArr);
     18         return this.run();
     19     }
     20     
     21     posts(txt, arr){//post消息
     22         //let id = this.id, sPos = this.sPos, ePos = this.ePos, arrs = arr || [];
     23         return {id:this.id, map:this.map, arr:arr || [], sPos:this.sPos, ePos:this.ePos, txt:txt}
     24     }
     25     
     26     isPath(x, y){//isPath = true 合法路径 = isBanPath === undefined
     27         let isPath = false, ym = this.mapArr.get(y), xm; //console.log(ym);  debugger;
     28         if(ym !== undefined){
     29             xm = ym.get(x);
     30             if(xm !== undefined){
     31                 if(xm.isBanPath === undefined){isPath = true;}
     32             }
     33         }
     34         //if(this.mapArr[y] !== undefined && this.mapArr[y][x] !== undefined && this.mapArr[y][x].isPath === 1){isPath = true;}
     35         return isPath;
     36     }
     37     
     38     getEqual(arr, x, y){//获取目标数组相同的坐标
     39         let isPos = false;
     40         if(arr.length === 0){
     41             isPos = false;
     42         }else{
     43             isPos = arr.some(function (o){return o.x === x && o.y === y;});
     44         }
     45         return isPos;
     46     }
     47 
     48     getDot(x, y){//获取周围8个方向坐标
     49         return [{x:x-1,y:y},{x:x+1,y:y},{x:x,y:y-1},{x:x,y:y+1},{x:x-1,y:y-1},{x:x+1,y:y+1},{x:x+1,y:y-1},{x:x-1,y:y+1}]
     50     }    
     51     
     52     getNewDot(setPos, pos){//重定义起点或终点
     53         let dot = setPos, pointDot, k, arr = [], arrs = [], g, end, maxMachT = 0;
     54         while(!end && maxMachT < this.maxMach){
     55             maxMachT++;
     56             pointDot = this.getDot(dot.x, dot.y);
     57             for(k in pointDot){
     58                 g = Math.round(Math.sqrt(Math.abs(pointDot[k].x - pos.x) + Math.abs(pointDot[k].y - pos.y)) * 100) / 100;
     59                 if(!this.isPath(pointDot[k].x, pointDot[k].y)){//不合法
     60                     arr.push({x:pointDot[k].x, y:pointDot[k].y, g:g});
     61                     arr.sort(function(a, b){return a.g - b.g;});
     62                 }else{//合法
     63                     arrs.push({x:pointDot[k].x, y:pointDot[k].y, g:g});
     64                     arrs.sort(function(a, b){return a.g - b.g;});
     65                 }
     66                 if(arrs.length > 0){end = true;}
     67             }
     68             dot = {x:arr[0].x, y:arr[0].y, g:arr[0].g}; arr = []; 
     69         }
     70         if(!arrs[0].x || !arrs[0].y){return this.posts("没有符合的坐标");}
     71         return {x:arrs[0].x, y:arrs[0].y};
     72     }
     73     
     74     run(){
     75         if(this.sPos.x === undefined || this.ePos.x === undefined){return this.posts("没有符合的坐标");}
     76         let sPos = this.sPos, ePos = this.ePos, point, key, i, newPoint, ger, gers, g, h, f, maxMachT = 0;
     77         this.openArr[0] = {x : sPos.x, y : sPos.y, f : 0, p : 0, ger : 0}
     78         while(this.openArr.length > 0){
     79             maxMachT++;
     80             point = this.openArr[0]; this.closeArr.push(point); this.openArr.splice(0,1);
     81             key = this.closeArr.length - 1;//设置当前节点
     82             newPoint = this.getDot(point.x, point.y);//获取周围点
     83             for(i in newPoint){//设置周围点
     84                 ger = Math.round(Math.sqrt(Math.abs(newPoint[i].x - point.x) + Math.abs(newPoint[i].y - point.y)) * 100) / 100;//到当前节点的曼哈顿距离,保留两位小数点
     85                 gers = ger + point.ger;
     86                 g = Math.round(gers * 100) / 100;
     87                 h = Math.abs(newPoint[i].x - ePos.x) + Math.abs(newPoint[i].y - ePos.y);
     88                 f = g + h;
     89                 if(this.isPath(newPoint[i].x, newPoint[i].y) && !this.getEqual(this.openArr, newPoint[i].x, newPoint[i].y) && !this.getEqual(this.closeArr, newPoint[i].x, newPoint[i].y)){this.openArr.push({x:newPoint[i].x, y:newPoint[i].y, f:f, p:key, ger:ger});}
     90             }
     91             this.openArr.sort(function(a, b){return a.f - b.f;});//排序
     92             if(this.getEqual(this.closeArr, ePos.x, ePos.y) || this.getEqual(this.openArr, ePos.x, ePos.y)){//end
     93                 this.minPath.unshift(this.closeArr[key]);
     94                 while(this.minPath.length > 0){
     95                     if(this.minPath[0].p == 0){return this.posts('success', this.minPath);}else{this.minPath.unshift(this.closeArr[this.minPath[0].p]);}
     96                 }
     97             }else if(maxMachT === this.maxMach){
     98                 return this.posts("没有符合的坐标");
     99             }
    100         }
    101         return this.posts("没有符合的坐标");
    102     }
    103     
    104 }
  • 相关阅读:
    滑雪
    2084 数塔HDU
    括号匹配(二)
    项链
    单调递增最长子序列
    矩形嵌套
    最长公共子序列
    poj3253
    表达式求值
    颜色16进制代码表显示和16进制数值对比显示方便查找
  • 原文地址:https://www.cnblogs.com/weihexinCode/p/12318344.html
Copyright © 2011-2022 走看看