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  • 392. Is Subsequence

    Given a string s and a string t, check if s is subsequence of t.

    You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100).

    A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace" is a subsequence of "abcde" while "aec" is not).

    Example 1:
    s = "abc", t = "ahbgdc"

    Return true.

    Example 2:
    s = "axc", t = "ahbgdc"

    Return false.

    Follow up:
    If there are lots of incoming S, say S1, S2, ... , Sk where k >= 1B, and you want to check one by one to see if T has its subsequence. In this scenario, how would you change your code?

    Credits:
    Special thanks to @pbrother for adding this problem and creating all test cases.

    class Solution {
        public boolean isSubsequence(String s, String t) {
            if (t.length() == 0 && s.length() == 0) return true;
            if(s.length() == 0) return true;
            if(t.length() == 0) return false;
            int ind = 0;
            
            for(int i = 0; i < t.length(); i++){
                if(s.charAt(ind) == t.charAt(i)){
                    if(ind == s.length() - 1) return true;
                    ind++;
                }
            }
            return false;
        }
    }

    非dp方法,匹配完就是true,匹配不完就是false

    然后试了两个dp还memory limit了草

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  • 原文地址:https://www.cnblogs.com/wentiliangkaihua/p/12868318.html
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