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  • 转 【解决方案】C#中使用Newtonsoft创建JSON字符串

    在很多涉及到网络通讯的地方,往往会用到JSON,初次接触这个东西,真的很令人头痛。不过有了Newtonsoft,这一切就变得出奇地简单:

    1、创建一个JSON

    String apiClass = "apiClass";
    String apiCommand = "apiCommand";
    String apiJsonParam = "apiJsonParam";
    
    JObject postedJObject = new JObject();
    postedJObject.Add("class", apiClass);
    postedJObject.Add("cmd", apiCommand);
    postedJObject.Add("param", apiJsonParam);
    String paramString = postedJObject.ToString(Newtonsoft.Json.Formatting.None, null);

    是不是很简单?
    那么paramString 的结果是什么呢?

    {"class":"apiClass","cmd":"apiCommand","param":"apiJsonParam"}

    格式化一下

    {
    	"class": "apiClass",
    	"cmd": "apiCommand",
    	"param": "apiJsonParam"
    }

    2、再创建一个嵌套的

    String apiClass = "apiClass";
    String apiCommand = "apiCommand";
    
    JObject postedJObject = new JObject();
    postedJObject.Add("class", apiClass);
    postedJObject.Add("cmd", apiCommand);
    
    String param1 = "param1";
    String param2 = "param2";
    JObject apiJsonParam = new JObject();
    apiJsonParam.Add("param1", param1);
    apiJsonParam.Add("param2", param2);
    
    postedJObject.Add("param", apiJsonParam);
    String paramString = postedJObject.ToString(Newtonsoft.Json.Formatting.None, null);

    格式化的字符串呢?

    {
      "class": "apiClass",
      "cmd": "apiCommand",
      "param": {
        "param1": "param1",
        "param2": "param2"
      }
    }

    3、再来一个添加了数组的

    String apiClass = "apiClass";
    String apiCommand = "apiCommand";
    
    JObject postedJObject = new JObject();
    postedJObject.Add("class", apiClass);
    postedJObject.Add("cmd", apiCommand);
    
    String param1 = "param1";
    String param2 = "param2";
    JObject apiJsonParam = new JObject();
    apiJsonParam.Add("param1", param1);
    apiJsonParam.Add("param2", param2);
    
    postedJObject.Add("param", apiJsonParam);
    
    JArray jArray = new JArray();
    
    JObject arr1 = new JObject();
    arr1.Add("arr1", "this is arr1");
    jArray.Add(arr1);
    
    JObject arr2 = new JObject();
    arr2.Add("arr2", "this is arr2");
    jArray.Add(arr2);
    
    postedJObject.Add("jarray", jArray);
    String paramString = postedJObject.ToString(Newtonsoft.Json.Formatting.Indented, null);

    那么JSON字符串又是怎么样呢?

    {
      "class": "apiClass",
      "cmd": "apiCommand",
      "param": {
        "param1": "param1",
        "param2": "param2"
      },
      "jarray": [
        {
          "arr1": "this is arr1"
        },
        {
          "arr2": "this is arr2"
        }
      ]
    }

    是不是很简单?

    转自:https://blog.csdn.net/u013667796/article/details/83826592

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  • 原文地址:https://www.cnblogs.com/wl-blog/p/13091518.html
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