zoukankan      html  css  js  c++  java
  • 每日算法

    每日算法

    those times when you get up early and you work hard; those times when you stay up late and you work hard; those times when don’t feel like working — you’re too tired, you don’t want to push yourself — but you do it anyway. That is actually the dream. That’s the dream. It’s not the destination, it’s the journey. And if you guys can understand that, what you’ll see happen is that you won’t accomplish your dreams, your dreams won’t come true, something greater will. mamba out


    那些你早出晚归付出的刻苦努力,你不想训练,当你觉的太累了但还是要咬牙坚持的时候,那就是在追逐梦想,不要在意终点有什么,要享受路途的过程,或许你不能成就梦想,但一定会有更伟大的事情随之而来。 mamba out~

    2020.3.29


    我太菜了 今天开始补cfdiv3

    CF#629Div3 A

    #include <iostream>
    #include <algorithm>
    #include <cstdio>
    #include <cstring>
    
    using namespace std;
    int n;
    int main()
    {
    	cin >> n;
    	int a, b ;
    	while(n --)	
    	{
    		cin >> a >> b;
    		if(a % b == 0)printf("0
    ");
    		else{ 
    			printf("%d
    ",b - (a % b));
    		}
    	}
    	return 0;
    } 
    

    CF#629Div3 B

    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<iostream>
    #include<cmath>
     
    using namespace std;
     
    int main()
    {
    	int t, ii, n, k, sum, i, j;
    	scanf("%d", &t);
    	for (ii = 0; ii<t; ii++) 
    	{
    		scanf("%d %d", &n, &k);
    		sum = 0;
    		k--;
    		for (i = 0;; i++)
    		{
    			if (sum + i + 1 > k)
    			{
    				break;
    			}
    			sum += i + 1;
    		}
    		k -= sum;
    		i++;
    		for (j = 0; j<n; j++) 
    		{
    			if (j == n - i - 1 || j == n - k - 1)
    			{
    				printf("b");
    			}
    			else
    			{
    				printf("a");
    			}
    		}
    		printf("
    ");
    	}
    	return 0;
    }
    

    CF#629Div3 C

    #include <iostream>
    #include <algorithm>
    #include <cstdio>
    #include <cstring>
    
    using namespace std;
    
    void func()
    {
    	int n;
    	cin >> n;
    	string s , a , b;
    	cin >> s;
    	int flag = 0;
    	for(int i = 0;i < s.size() ;i ++)
    	{
    		if(s[i] == '2')
    		{
    			if(flag == 0)
    				a+='1',b+='1';
    			else 
    				a+='0',b+='2';	
    		}
    		else if(s[i] == '0')a+='0',b+='0';
    		else{
    			if(flag == 0)
    			{
    				flag = 1;
    				a+='1';b+='0'; 
    			}
    			else{
    				a += '0';b += '1';
    			}
    		}	
    	}
    	cout << a << endl;
    	cout << b << endl;	
    }
    int main()
    {
    	int t;cin >> t;
    	while(t--)
    	{
    		func();	
    	}	
    	return 0;
    } 
    

    摆动序列

    假dp 真搜索

    #include <iostream>
    #include <algorithm>
    #include <cstdio>
    #include <cstring>
    
    using namespace std;
    int n, ans;
    bool vis[25];
    void dfs(int a ,int b)
    {
    	if(b > a){
    		for(int i = 1;i < a ;i ++)
    		{
    			if(!vis[i])
    			{
    				ans++;
    				vis[i] = 1;
    				dfs(b , i);
    				vis[i] = 0;
    			}
    		}
    	}
    	else if(a > b){ 
    		for(int i = a + 1;i <= n;i ++)
    		{
    			if(!vis[i])
    			{	
    				ans++;
    				vis[i] = 1;
    				dfs(b , i);
    				vis[i] = 0;
    			}
    		}
    	}
    }
    int main()
    {
    	cin >> n;
    	for(int i = 1;i <= n ;i ++)
    	{
    		vis[i] = 1;
    		for(int j = 1;j <= n ;j ++)
    		{
    			if(i != j)
    			{
    				ans++;
    				vis[j] = 1;
    				dfs(i , j);
    				vis[j] = 0;
    			}
    		}
    	}
    	cout << ans << endl;
    	return 0;
    }
    
    

    拦截导弹

    (o(n^{2}))

    #include <iostream>
    #include <algorithm>
    #include <cstdio>
    
    using namespace std;
    const int N = 100005;
    int f[N], a[N], n;
    
    int main()
    {
    	while(~scanf("%d",&a[++n]));n--;
    	int ans1 = 0, ans2 = 0;
    	for(int i = n;i >= 1 ;i --)
    	{
    		f[i] = 1;
    		for(int j = i + 1;j <= n ;j ++)
    		{
    			if(a[j] <= a[i])
    				f[i] = max(f[i],f[j] + 1);
    		}
    		ans1 = max(ans1,f[i]);
    	}
    	for(int i = 1;i <= n ;i ++)
    	{
    		f[i] = 1;
    		for(int j = 1;j < i ;j ++)
    		{
    			if(a[j] < a[i])
    				f[i] = max(f[i],f[j] + 1);
    		}
    		ans2 = max(ans2,f[i]);
    	}
    	printf("%d
    %d",ans1,ans2);
    	return 0;
    }
    
  • 相关阅读:
    python链接Hive
    input type=file输入框
    JQ剪辑图片插件,适用于移动端和PC端
    随笔
    Js获取当前日期时间及其它操作
    SQL中like语句的索引使用
    MS SQLSERVER 数据库表存储结构
    Jdom 解析 XML
    sqlserver 查询时,datetime的相关函数
    xml转换String输出
  • 原文地址:https://www.cnblogs.com/wlw-x/p/12595469.html
Copyright © 2011-2022 走看看