题目链接:http://abc043.contest.atcoder.jp/tasks/abc043_b
Time limit : 2sec / Memory limit : 256MB
Score : 200 points
Problem Statement
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the 0
key, the 1
key and the backspace key.
To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:
- The
0
key: a letter0
will be inserted to the right of the string. - The
1
key: a letter1
will be inserted to the right of the string. - The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.
Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter 0
stands for the 0
key, the letter 1
stands for the 1
key and the letter B
stands for the backspace key. What string is displayed in the editor now?
Constraints
- 1≦|s|≦10 (|s| denotes the length of s)
- s consists of the letters
0
,1
andB
. - The correct answer is not an empty string.
Input
The input is given from Standard Input in the following format:
s
Output
Print the string displayed in the editor in the end.
Sample Input 1
01B0
Sample Output 1
00
Each time the key is pressed, the string in the editor will change as follows: 0
, 01
, 0
, 00
.
Sample Input 2
0BB1
Sample Output 2
1
Each time the key is pressed, the string in the editor will change as follows: 0
, (empty)
, (empty)
, 1
.
题解:栈 我也不知道为啥有三组数据过不了 先放这
大晚上来补这道题 后来才发现自己的思路错了 后面输出的顺序完全反了 (栈的特性 最后只需要改改顺序就行了)思路错了居然还过了一大半的数据 有毒 ...
1 #include <iostream> 2 #include <algorithm> 3 #include <cstring> 4 #include <cstdio> 5 #include <vector> 6 #include <cstdlib> 7 #include <iomanip> 8 #include <cmath> 9 #include <ctime> 10 #include <map> 11 #include <set> 12 #include <queue> 13 #include <stack> 14 using namespace std; 15 #define lowbit(x) (x&(-x)) 16 #define max(x,y) (x>y?x:y) 17 #define min(x,y) (x<y?x:y) 18 #define MAX 100000000000000000 19 #define MOD 1000000007 20 #define pi acos(-1.0) 21 #define ei exp(1) 22 #define PI 3.141592653589793238462 23 #define INF 0x3f3f3f3f3f 24 #define mem(a) (memset(a,0,sizeof(a))) 25 typedef long long ll; 26 ll gcd(ll a,ll b){ 27 return b?gcd(b,a%b):a; 28 } 29 bool cmp(int x,int y) 30 { 31 return x>y; 32 } 33 const int N=10005; 34 const int mod=1e9+7; 35 int main() 36 { 37 std::ios::sync_with_stdio(false); 38 string a; 39 cin>>a; 40 int len=a.length(); 41 stack <char> q ; 42 for(int i=0;i<len;i++){ 43 if(a[i]=='1') q.push('1'); 44 else if(a[i]=='0') q.push('0'); 45 else if(a[i]=='B'){ 46 if(q.size()>0) 47 q.pop(); 48 } 49 } 50 char b[20]; 51 int t=0,i; 52 while(q.size()>0){ 53 b[t++]=q.top(); 54 q.pop(); 55 } 56 for(i=t-1;i>=0;i--) 57 cout<<b[i]; 58 cout<<endl; 59 return 0; 60 }