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  • python中if else流程判断

    _username='Lily'
    _password='123'
    
    username=input("username:")
    password=input("password:")
    
    if _username==username and _password==password:
        print("Welcome user {name} login....".format(name=username))
    else:
        print("Invalid username or password")

    输入结果

    F:pypyProjectvenvScriptspython.exe F:/py/pyProject/Day3.py
    username:Lily
    password:123
    Welcome user Lily login....
    
    Process finished with exit code 0

     2.

    grade_of_Lucy = 85
    guess_grade = int(input("guess grade:"))
    if guess_grade == grade_of_Lucy:
        print("yes,you got it")
    elif guess_grade > grade_of_Lucy:
        print("think bigger")
    else:
        print("think smaller")
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  • 原文地址:https://www.cnblogs.com/wz123/p/9651712.html
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