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  • 服务器需求(牛客)


    #include <cstdio>
    #define MAXN 400010
    long long num[MAXN];
    long long max(long long a, long long b) {return a > b ? a : b;}
    long long tree[MAXN * 4];
    void build(int node, int l, int r) {
        if (l == r) {
            tree[node] = num[l];
            return;
        }
        int mid = (l + r) >> 1;
        build(node * 2, l, mid);
        build(node * 2 + 1, mid + 1, r);
        tree[node] = max(tree[node * 2], tree[node * 2 + 1]);
    }
    int x, y;
    void change(int node, int l, int r, int pos, int k) {
        if (l == r) {
            tree[node] = k * 1ll;
            return;
        }
        int mid = (l + r) >> 1;
        if (pos <= mid) change(node * 2, l, mid, pos, k);
        else change(node * 2 + 1, mid + 1, r, pos, k);
        tree[node] = max(tree[node * 2], tree[node * 2 + 1]);
    }
    int main() {
        int n, m, q; scanf("%d %d %d", &n, &m, &q);
        x = 1, y = n;
        long long sum = 0, mx = 0;
        for (int i = 1; i <= n; i++) {
            scanf("%lld", &num[i]);
            mx = max(mx, num[i]);
            sum += num[i];
        }
        build(1, 1, n);
        while (q--) {
            printf("%lld\n", max(tree[1], sum / m + (sum % m == 0 ? 0 : 1)));
            int x; long long a; scanf("%d %lld", &x, &a);
            sum -= num[x]; num[x] = a;
            sum += a;
            change(1, 1, n, x, a);
        }
        printf("%lld\n", max(tree[1], sum / m + (sum % m == 0 ? 0 : 1)));
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/wzxbeliever/p/15632212.html
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