095 Unique Binary Search Trees II 不同的二叉查找树 II

给出 n，问由 1...n 为节点组成的不同的二叉查找树有多少种？
例如，
给出 n = 3，则有 5 种不同形态的二叉查找树：
   1         3     3      2      1
           /     /      /      
     3     2     1      1   3      2
    /     /                       
   2     1         2                 3
详见：https://leetcode.com/problems/unique-binary-search-trees-ii/description/

Java实现：

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    public List<TreeNode> generateTrees(int n) {
        if(n<1){
            return new ArrayList<TreeNode>();
        }
        return generateTrees(1,n);
    }
    private ArrayList<TreeNode> generateTrees(int left, int right){
        ArrayList<TreeNode> res = new ArrayList<TreeNode>();
        if (left > right){
            res.add(null);
            return res;
        }
        for (int i = left; i <= right; i++){
            ArrayList<TreeNode> lefts = generateTrees(left, i-1);//以i作为根节点，左子树由[1,i-1]构成
            ArrayList<TreeNode> rights = generateTrees(i+1, right);//右子树由[i+1, n]构成
            for (int j = 0; j < lefts.size(); j++){
                for (int k = 0; k < rights.size(); k++){
                    TreeNode root = new TreeNode(i);
                    root.left = lefts.get(j);
                    root.right = rights.get(k);
                    res.add(root);//存储所有可能行
                }
            }
        }
        return res;
    }
}