详见:https://leetcode.com/problems/diagonal-traverse/description/
C++:
class Solution {
public:
vector<int> findDiagonalOrder(vector<vector<int>>& matrix)
{
if (matrix.empty() || matrix[0].empty())
{
return {};
}
int m = matrix.size(), n = matrix[0].size(), r = 0, c = 0, k = 0;
vector<int> res(m * n);
vector<vector<int>> dirs{{-1,1}, {1,-1}};
for (int i = 0; i < m * n; ++i)
{
res[i] = matrix[r][c];
r += dirs[k][0];
c += dirs[k][1];
if (r >= m)
{
r = m - 1;
c += 2;
k = 1 - k;
}
if (c >= n)
{
c = n - 1;
r += 2;
k = 1 - k;
}
if (r < 0)
{
r = 0;
k = 1 - k;
}
if (c < 0)
{
c = 0;
k = 1 - k;
}
}
return res;
}
};
参考:http://www.cnblogs.com/grandyang/p/6414461.html