详见:https://leetcode.com/problems/beautiful-arrangement/description/
C++:
class Solution {
public:
int countArrangement(int N)
{
int res = 0;
vector<int> visited(N + 1, 0);
helper(N, visited, 1, res);
return res;
}
void helper(int N, vector<int>& visited, int pos, int& res)
{
if (pos > N)
{
++res;
return;
}
for (int i = 1; i <= N; ++i)
{
if (visited[i] == 0 && (i % pos == 0 || pos % i == 0))
{
visited[i] = 1;
helper(N, visited, pos + 1, res);
visited[i] = 0;
}
}
}
};
参考:http://www.cnblogs.com/grandyang/p/6533276.html