zoukankan      html  css  js  c++  java
  • [建树(非二叉树)] 1106. Lowest Price in Supply Chain (25)

    1106. Lowest Price in Supply Chain (25)

    A supply chain is a network of retailers(零售商), distributors(经销商), and suppliers(供应商)-- everyone involved in moving a product from supplier to customer.

    Starting from one root supplier, everyone on the chain buys products from one's supplier in a price P and sell or distribute them in a price that is r% higher than P. Only the retailers will face the customers. It is assumed that each member in the supply chain has exactly one supplier except the root supplier, and there is no supply cycle.

    Now given a supply chain, you are supposed to tell the lowest price a customer can expect from some retailers.

    Input Specification:

    Each input file contains one test case. For each case, The first line contains three positive numbers: N (<=105), the total number of the members in the supply chain (and hence their ID's are numbered from 0 to N-1, and the root supplier's ID is 0); P, the price given by the root supplier; and r, the percentage rate of price increment for each distributor or retailer. Then N lines follow, each describes a distributor or retailer in the following format:

    Ki ID[1] ID[2] ... ID[Ki]

    where in the i-th line, Ki is the total number of distributors or retailers who receive products from supplier i, and is then followed by the ID's of these distributors or retailers. Kj being 0 means that the j-th member is a retailer. All the numbers in a line are separated by a space.

    Output Specification:

    For each test case, print in one line the lowest price we can expect from some retailers, accurate up to 4 decimal places, and the number of retailers that sell at the lowest price. There must be one space between the two numbers. It is guaranteed that the all the prices will not exceed 1010.

    Sample Input:
    10 1.80 1.00
    3 2 3 5
    1 9
    1 4
    1 7
    0
    2 6 1
    1 8
    0
    0
    0
    
    Sample Output:
    1.8362 2
    #include <iostream>
    #include <cstdio>
    #include <cmath>
    #include <cstring>
    #include <algorithm>
    #include <vector>
    using namespace std;
    const int INF=1e9;
    const int maxn=100010;
    
    struct Node
    {
        int data;
        vector<int> child;
    }node[maxn];
    int min_deep=INF;
    int num[maxn]={0};
    
    void dfs(int s,int & deep)
    {
        if(node[s].child.size()==0)
        {
            num[deep]+=1;
            if(deep<min_deep)
            {
                min_deep=deep;
            }
            return ;
        }
        for(int i=0;i<node[s].child.size();i++)
        {
            int v=node[s].child[i];
            deep++;
            dfs(v,deep);
            deep--;
        }
    }
    
    int main()
    {
        int n;
        double p,r;
        cin>>n>>p>>r;
        for(int i=0;i<n;i++)
        {
            int k;
            cin>>k;
            int id;
            for(int j=0;j<k;j++)
            {
                cin>>id;
                node[i].child.push_back(id);
            }
        }
        int deep=0;
        dfs(0,deep);
        deep=min_deep;
        double sum=p;
        while(min_deep>0)
        {
            min_deep-=1;
            sum*=1.0+r/100;
        }
        //printf("debug:%d",min_deep);
        printf("%.4lf %d
    ",sum,num[deep]);
    }
  • 相关阅读:
    ImgeView的scaleType
    linux 重命名文件和文件夹
    退出整个应用解决方案
    md5验证文件
    cat和echo重定向,文件读写
    Nginx下配置Https 配置文件(vue)
    Nginx下配置Https证书详细过程
    大型系列课程之-七夕告白之旅Electron篇
    大型系列课程之-七夕告白之旅vbs篇
    vue前后分离项目部署(不同端口号,nginx反向代理解决跨域问题)
  • 原文地址:https://www.cnblogs.com/xiongmao-cpp/p/6475566.html
Copyright © 2011-2022 走看看