原文题目:
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
读题:
有两个有序整数数组nums1和nums2,将nums2合并到nums1中,根据提示已经假设了nums1有足够的空间容纳nums1和nums2的所有元素,同时nums1和nums2的长度分别为m和n
由于合并后的数组需要放入原nums1数组,为了在合并的过程中又不影响原先nums1的数据获取,因此可以从尾到前依次添加,这样nums1前面的数据才不会受到影响
class Solution(object): def merge(self, nums1, m, nums2, n): """ :type nums1: List[int] :type m: int :type nums2: List[int] :type n: int :rtype: void Do not return anything, modify nums1 in-place instead. """ p = m - 1 q = n - 1 k = m + n -1 while p >= 0 and q >= 0: if nums1[p] >= nums2[q]: nums1[k] = nums1[p] p -= 1 k -= 1 else: nums1[k] = nums2[q] q -= 1 k -= 1 '''这里判断nums2是否还有元素,则加入到nums1中,如果nums2中没有元素了,则说明已经合并完成,不做任何处理''' while q >= 0: nums1[k] = nums2[q] q -= 1 k -= 1