zoukankan      html  css  js  c++  java
  • 463. Island Perimeter

    ##题目 You are given a map in form of a two-dimensional integer grid where 1 represents land and 0 represents water. Grid cells are connected horizontally/vertically (not diagonally). The grid is completely surrounded by water, and there is exactly one island (i.e., one or more connected land cells). The island doesn't have "lakes" (water inside that isn't connected to the water around the island). One cell is a square with side length 1. The grid is rectangular, width and height don't exceed 100. Determine the perimeter of the island.

    Example:

    [[0,1,0,0], [1,1,1,0], [0,1,0,0], [1,1,0,0]]

    Answer: 16 Explanation: The perimeter is the 16 yellow stripes in the image below:
    ##分析 求岛的周长,其中相邻的1和0形成一条边
    ##解答 ###解法1:(我)异或(185ms)

    public class Solution {
        public int islandPerimeter(int[][] grid) {
            int perimeter = 0;
            for (int i = 0; i < grid.length; i++){
                for (int j = 0; j < grid[0].length; j++){
                    if (i == 0 && j == 0)//第一行第一列(左上)
                        perimeter += ((grid[i][j] ^ 0) + (grid[i][j] ^ 0));
                    else if (i == 0 && j != 0)//第一行(左上)
                        perimeter += ((grid[i][j] ^ 0) + (grid[i][j] ^ grid[i][j-1]));
                    else if (j == 0 && i != 0)//第一列(左上)
                        perimeter += ((grid[i][j] ^ grid[i-1][j]) + (grid[i][j] ^ 0));
                    else
                        perimeter += ((grid[i][j] ^ grid[i-1][j]) + (grid[i][j] ^ grid[i][j-1]));
                        
                    
                    if (i == grid.length - 1)//最后一行(下)
                        perimeter += grid[i][j] ^ 0 ;
                    if (j == grid[0].length - 1)//最后一列(右)
                        perimeter += grid[i][j] ^ 0;
                    
                }
            }
            return perimeter;
        }
    }
    

     
    ###解法2:(我)选出1,计算其上下左右0的个数(155ms√)

    public class Solution {
        public int islandPerimeter(int[][] grid) {
            int perimeter = 0;
            for (int i = 0; i < grid.length; i++){
                for (int j = 0; j < grid[0].length; j++){
                    if (grid[i][j] == 1){
                        if (i == 0 || grid[i-1][j] == 0){perimeter++;}//up
                        if (j == 0 || grid[i][j-1] == 0){perimeter++;}//left
                        if (i == grid.length - 1 || grid[i+1][j] == 0){perimeter++;}//down
                        if (j == grid[0].length - 1 || grid[i][j+1] == 0){perimeter++;}//right
                    }
                    
                }
            }
            return perimeter;
        }
    }
    
  • 相关阅读:
    【原】使用Spring自带的JdbcTemplate。
    【原】MyBatis执行DDL:create table,drop table等等
    【转】java获取当前路径的几种方法
    【原】Java程序调用远程Shell脚本
    [转载] 使用Kettle进行数据迁移(ETL)
    appium原理
    python之global关键字的用法
    python之selenium定位(xpath)
    android 稳定性monkey测试
    python之selenium随记(几种等待的用法)
  • 原文地址:https://www.cnblogs.com/xuehaoyue/p/6412707.html
Copyright © 2011-2022 走看看