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  • CF Tavas and Nafas

     Tavas and Nafas
    time limit per test
    1 second
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.

    His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score with Nafas via text, so he has no choice but to send this number using words.

    He ate coffee mix without water again, so right now he's really messed up and can't think.

    Your task is to help him by telling him what to type.

    Input

    The first and only line of input contains an integer s (0 ≤ s ≤ 99), Tavas's score.

    Output

    In the first and only line of output, print a single string consisting only from English lowercase letters and hyphens ('-'). Do not use spaces.

    Sample test(s)
    input
    6
    output
    six
    input
    99
    output
    ninety-nine
    input
    20
    output
    twenty




    英语基础题
    #include <iostream>
    #include <cmath>
    #include <cstring>
    #include <cstdio>
    #include <string>
    #include <algorithm>
    #include <cctype>
    #include <queue>
    #include <map>
    using    namespace    std;
    
    char    HIGH[][20] = {"ten","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"};
    char    TEN[][20] = {"ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen",
    "seventeen","eighteen","nineteen"};
    char    LOW[][20] = {"zero","one","two","three","four","five","six","seven","eight",
    "nine"};
    int    main(void)
    {
        string    s;
        int    len;
    
        while(cin >> s)
        {
            len = s.size();
            if(len == 1)
                cout << LOW[s[0] - '0'] << endl;
            else    if(s[0] == '1')
                cout << TEN[s[1] - '0'] << endl;
            else
            {
                if(s[1] == '0')
                    cout << HIGH[s[0] - '1'] << endl;
                else
                    cout << HIGH[s[0] - '1'] << '-' << LOW[s[1] - '0'] << endl;
            }
        }
    
        return    0;
    }
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  • 原文地址:https://www.cnblogs.com/xz816111/p/4433716.html
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