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  • Oracle sql 复习题目总结

    sql 题目一

    表结构

    1、表名:g_cardapply
    字段(字段名/类型/长度):
    apply_no varchar8; //申请单号(关键字)
    apply_date date; //申请日期
    state varchar2; //申请状态
    2、表名:g_cardapplydetail
    字段(字段名/类型/长度):
    apply_no varchar8; //申请单号(关键字)
    name varchar30; //申请人姓名
    idcard varchar18; //申请人身份证号
    state varchar2; //申请状态
    其中,两个表的关联字段为申请单号。

    题目

    1、查询身份证号码为440401430103082的申请日期
    2、查询同一个身份证号码有两条以上记录的身份证号码及记录个数
    3、将身份证号码为440401430103082的记录在两个表中的申请状态均改为07
    4、删除cardapplydetail表中所有姓李的记录

    建表

    create table g_cardapply(
        apply_no varchar2(8),
        apply_date date not null,
        state varchar2(2) not null,
        constraint PK_APPLY_NO PRIMARY KEY (apply_no)
    );
    
    create table g_cardapplydetail(
        apply_no varchar2(8) ,
        apply_name varchar2(30) not null,
        idcard char(18) not null,
        state varchar2(2) not null,
        constraint PK_APPLY_DETAIL_NO PRIMARY KEY (apply_no),
        constraint FK_CARDAPPLY_DETAIL foreign key (apply_no) references g_cardapply(apply_no)
    );
        
    -- oracle字符串转日期,使用to_date函数
    insert into g_cardapply values('00000010',to_date('2011-11-12','yyyy-mm-dd'),'01');
    insert into g_cardapply values('00000011',to_date('2011-11-13','yyyy-mm-dd'),'01');
    insert into g_cardapply values('00000012',to_date('2011-11-14','yyyy-mm-dd'),'02');
    insert into g_cardapply values('00000013',to_date('2011-11-15','yyyy-mm-dd'),'03');
    insert into g_cardapply values('00000014',to_date('2011-11-16','yyyy-mm-dd'),'03');
    
    insert into g_cardapplydetail values('00000010','mary','440401430103082','01');
    insert into g_cardapplydetail values('00000011','david','440401430103083','01');
    insert into g_cardapplydetail values('00000012','mary','440401430103082','02');
    insert into g_cardapplydetail values('00000013','mike','440401430103084','03');
    insert into g_cardapplydetail values('00000014','mary','440401430103082','03');
    commit;
    

    求解

    1、查询身份证号码为440401430103082的申请日期

    select apply_date from g_cardapply a,g_cardapplydetail b
    where a.apply_no=b.apply_no and b.idcard='440401430103082';
    

    select apply_date from g_cardapply a inner join g_cardapplydetail b
    on a.apply_no=b.apply_no and b.idcard='440401430103082';
    

    2、查询同一个身份证号码有两条以上记录的身份证号码及记录个数

    select idcard,count(idcard) as records from g_cardapplydetail
    group by idcard having count(idcard)>=2;
    

    3、将身份证号码为440401430103082的记录在两个表中的申请状态均改为07

    update g_cardapplydetail set state='07' where idcard='440401430103082';
    
    -- 子查询
    update g_cardapply set state='07' where apply_no in (
        select apply_no from g_cardapplydetail where idcard='440401430103082'
    );
    commit;
    

    4、删除cardapplydetail表中所有姓李的记录

    -- 模糊查询
    delete from g_cardapplydetail where apply_name like '李%';
    

    sql 题目二

    有一个工厂,非常繁忙,同时在进行多个订单的生产任务。每个订单都有自己的订单编号(WORKORDER_ ID),每个订单要生产的物品要拆分成多个工序,这些工序并行进行,每个工序都有自己的编号STEP_ NBR,测试数据如下:

    create table projects(
        workorder_id varchar2(10) not null,
        step_nbr int not null,
        step_status char(1) not null,
        constraint PK_PROJECTS PRIMARY KEY (workorder_id,step_nbr)
    );
    
    --  C-完成  W-等待
    insert into projects values('ww023',0,'C');
    insert into projects values('ww023',1,'W');
    insert into projects values('ww023',2,'W');
    insert into projects values('ww024',0,'W');
    insert into projects values('ww024',1,'W');
    insert into projects values('ww025',0,'C');
    insert into projects values('ww025',1,'C');
    

    C-完成 W-等待

    请编写SQL语句,找出STEP_ NBR=0,其 STEP STATUS='C',同时本订单其它工序STEP_ STATUS均为W的订单,比如对以上数据的分析结果就是:

    WORKORDER_ID

    ww023

    要求:至少实现2种写法(多写更好),语句越短越好。

    一解:

    -- 条件1: 
    where step_nbr=0 and step_status='c'
    -- 条件2:
    'W’= ALL (select step_status from XXX where step_nbr> = 1)
    
    select workorder_id from projects p where p.step_nbr=0 and p.step_status='C' and 'W'= ALL (
    	select step_status from projects where step_nbr>=1 and workorder_id=p.workorder_id
    );
    

    二解:

    select workorder_id from projects p where step_status='C' 
    group by workorder_id having sum(step_nbr)=0;
    

    sql 题目三

    Northwind商贸公司,业务日益发展,公司OA系统正不断推出新版本以紧跟公司的发展。在OA系统中,有一员工角色表,情况如下:

    EMP_NAME EMP_ROLE
    陈城 W
    刘海 D
    刘海 O
    田亮 O
    王晓刚 D
    张玲 S
    张天明 D
    张天明 O

    其中: W–搬运工人 D–主任 O–高级职员 S–秘书

    OA开发组的SQL程序员张明得到了上级的一个任务:领导要求得到的高级职员信息表如下:

    EMP_NAME COMBINE_ROLE
    刘海 B
    田亮 O
    王晓刚 D
    张天明 B

    要求:
    1)只列出主任和高级职员的信息
    2)如果即是高级职员又是主任,用B表示其角色, 其它信息不用再显示 (只一条记录)。
    你能不能用单条SQL语句帮助张明实现这个查询?

    建表

    create table roles(
        emp_name varchar2(20) not null,
        emp_role char(1) not null,
        constraint pk_roles primary key(emp_name,emp_role)
     );
     
     -- 英文名
    insert into roles values('Mary','W');
    insert into roles values('David','D');
    insert into roles values('David','O');
    insert into roles values('Mike','O');
    insert into roles values('Kate','D');
    insert into roles values('Lucy','S');
    insert into roles values('Nick','D');
    insert into roles values('Nick','O');
    
    -- 中文名
    insert into roles values('陈城','W');
    insert into roles values('刘海','D');
    insert into roles values('刘海','O');
    insert into roles values('田亮','O');
    insert into roles values('王晓刚','D');
    insert into roles values('张玲','S');
    insert into roles values('张天明','D');
    insert into roles values('张天明','O');
    

    求解

    一解:

    select emp_name,'B' combine_role from roles where emp_role in ('D','O')
    group by emp_name having count(*)=2
    union
    select emp_name,max(emp_role) combine_role from roles where emp_role in ('D','O')
    group by emp_name having count(*)=1;
    

    二解:

    select emp_name, case when count(*)=1 then max(emp_role) else 'B' end as emp_role
    from roles where emp_role in ('D','O') group by emp_name;
    

    select emp_name, case when count(*)=2 then 'B' else max(emp_role) end as emp_role
    from roles where emp_role in ('D','O') group by emp_name;
    

    三解:

    select emp_name, substr('DOB',sum(instr('DO',emp_role)),1) combine_role from roles
    where emp_role in ('D','O')group by emp_name;
    
    -- instr:返回第二个参数在第一个参数中第一次出现的位置
    

    sql 题目四

    最近,经过你的努力,你得到了一份工作,成为了百货公司的一位经理。 到位后,你发现你的销售数据库中有两张表,一个是商店促销时间的日历,另一个是在促销期间的销售额列表。你需要编写一个查询,告诉我们在每次促销中哪位职员的销售额最高,这样可以给那个职员发绩效奖金。

    找出在各次促销活动中,销售量最高的销售员。
    请编制一条SQL来完成这个查询。(尽量考虑多种写法)

    建表

    -- 商店促销时间的日历
    create table promotions (
        promo_name varchar2(50) not null primary key,  -- 促销活动名称
        start_date date not null,                      -- 开始时间
        end_date date not null,                        -- 终止时间
        check(start_date<=end_date)
    );
    
    -- 促销期间的销售额表 (注意:该表只是保存促销期间的销售额)
    create table sales
    (
        ticket_nbr int not null primary key,  --销售票据编号 (自增)
        clerk_name varchar2(20) not null,     --销售员姓名
        sale_date date not null,              --销售日期
        sale_amount number(9,2) not null      --销售金额
    );
    
    insert into promotions values('spring sales',to_date('2009-2-1','yyyy/mm/dd'),to_date('2009-2-15','yyyy/mm/dd'));
    insert into promotions values('worker sale',to_date('2009-5-1','yyyy/mm/dd'),to_date('2009-5-4','yyyy/mm/dd'));
    insert into promotions values('children sale',to_date('2009-6-1','yyyy/mm/dd'),to_date('2009-6-1','yyyy/mm/dd'));
    insert into promotions values('national day sale',to_date('2009-10-1','yyyy/mm/dd'),to_date('2009-10-7','yyyy/mm/dd'));
    
    create sequence seq_nbr;
    
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-2-1','yyyy/mm/dd'),30);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-2-1','yyyy/mm/dd'),73);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-2-1','yyyy/mm/dd'),110);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-2-2','yyyy/mm/dd'),190);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-2-2','yyyy/mm/dd'),30);
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-2-2','yyyy/mm/dd'),92);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-2-3','yyyy/mm/dd'),130);
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-2-3','yyyy/mm/dd'),90);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-2-3','yyyy/mm/dd'),110);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-2-4','yyyy/mm/dd'),70);
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-2-4','yyyy/mm/dd'),9);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-2-5','yyyy/mm/dd'),88);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-2-5','yyyy/mm/dd'),70);
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-2-13','yyyy/mm/dd'),50);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-2-13','yyyy/mm/dd'),170);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-2-14','yyyy/mm/dd'),270);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-2-15','yyyy/mm/dd'),67.5);
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-5-1','yyyy/mm/dd'),280.5);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-5-1','yyyy/mm/dd'),190);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-5-1','yyyy/mm/dd'),113);
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-5-2','yyyy/mm/dd'),88);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-5-2','yyyy/mm/dd'),35.5); 
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-5-2','yyyy/mm/dd'),125);
    insert into sales values(seq_nbr.nextval,'david',  to_date('2009-5-3','yyyy/mm/dd'),92);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-5-3','yyyy/mm/dd'),93);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-5-3','yyyy/mm/dd'),167);
    insert into sales values(seq_nbr.nextval,'david',  to_date('2009-5-4','yyyy/mm/dd'),123.5);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-5-4','yyyy/mm/dd'),200);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-5-4','yyyy/mm/dd'),2);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-6-1','yyyy/mm/dd'),190);
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-6-1','yyyy/mm/dd'),110.5);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-6-1','yyyy/mm/dd'),213);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-10-1','yyyy/mm/dd'),1123);
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-10-1','yyyy/mm/dd'),780);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-10-1','yyyy/mm/dd'),310);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-10-2','yyyy/mm/dd'),139);
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-10-2','yyyy/mm/dd'),1110.5);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-10-2','yyyy/mm/dd'),998);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-10-3','yyyy/mm/dd'),120);
    insert into sales values(seq_nbr.nextval,'mary',to_date('2009-10-4','yyyy/mm/dd'),10);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-10-4','yyyy/mm/dd'),234);
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-10-5','yyyy/mm/dd'),110.5);
    insert into sales values(seq_nbr.nextval,'tom',to_date('2009-10-6','yyyy/mm/dd'),23);
    insert into sales values(seq_nbr.nextval,'david',to_date('2009-10-7','yyyy/mm/dd'),10.5); 
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-2-1','yyyy/mm/dd'),30);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-2-1','yyyy/mm/dd'),73);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-2-1','yyyy/mm/dd'),110);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-2-2','yyyy/mm/dd'),190);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-2-2','yyyy/mm/dd'),30);
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-2-2','yyyy/mm/dd'),92);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-2-3','yyyy/mm/dd'),130);
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-2-3','yyyy/mm/dd'),90);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-2-3','yyyy/mm/dd'),110);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-2-4','yyyy/mm/dd'),70);
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-2-4','yyyy/mm/dd'),9);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-2-5','yyyy/mm/dd'),88);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-2-5','yyyy/mm/dd'),70);
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-2-13','yyyy/mm/dd'),50);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-2-13','yyyy/mm/dd'),170);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-2-14','yyyy/mm/dd'),270);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-2-15','yyyy/mm/dd'),67.5);
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-5-1','yyyy/mm/dd'),280.5);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-5-1','yyyy/mm/dd'),190);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-5-1','yyyy/mm/dd'),113);
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-5-2','yyyy/mm/dd'),88);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-5-2','yyyy/mm/dd'),35.5); 
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-5-2','yyyy/mm/dd'),125);
    insert into sales values(seq_nbr.nextval,'王海',  to_date('2009-5-3','yyyy/mm/dd'),92);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-5-3','yyyy/mm/dd'),93);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-5-3','yyyy/mm/dd'),167);
    insert into sales values(seq_nbr.nextval,'王海',  to_date('2009-5-4','yyyy/mm/dd'),123.5);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-5-4','yyyy/mm/dd'),200);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-5-4','yyyy/mm/dd'),2);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-6-1','yyyy/mm/dd'),190);
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-6-1','yyyy/mm/dd'),110.5);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-6-1','yyyy/mm/dd'),213);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-10-1','yyyy/mm/dd'),1123);
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-10-1','yyyy/mm/dd'),780);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-10-1','yyyy/mm/dd'),310);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-10-2','yyyy/mm/dd'),139);
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-10-2','yyyy/mm/dd'),1110.5);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-10-2','yyyy/mm/dd'),998);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-10-3','yyyy/mm/dd'),120);
    insert into sales values(seq_nbr.nextval,'高春梅',to_date('2009-10-4','yyyy/mm/dd'),10);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-10-4','yyyy/mm/dd'),234);
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-10-5','yyyy/mm/dd'),110.5);
    insert into sales values(seq_nbr.nextval,'刘万理',to_date('2009-10-6','yyyy/mm/dd'),23);
    insert into sales values(seq_nbr.nextval,'王海',to_date('2009-10-7','yyyy/mm/dd'),10.5); 
    

    求解

    一解:

    select p.promo_name, s.clerk_name, sum(s.sale_amount) top_sale
    from promotions p inner join sales s on s.sale_date between p.start_date and p.end_date
    group by p.promo_name,s.clerk_name,p.start_date,p.end_date
    having sum(s.sale_amount) > all(
           select sum(s2.sale_amount) from sales s2
           where s.clerk_name <> s2.clerk_name and s2.sale_date between p.start_date and p.end_date
           group by s2.clerk_name
    );
    

    二解:

    SELECT s1.clerk_name,p.promo_name,p.start_date,p.end_date,SUM(s1.sale_amount)
    FROM sales s1 INNER JOIN promotions p ON s1.sale_date BETWEEN p.start_date AND p.end_date
    group by s1.clerk_name,p.promo_name,p.start_date,p.end_date
    HAVING SUM(s1.sale_amount)>= ALL(
            SELECT SUM(s2.sale_amount) FROM sales s2
            WHERE s2.sale_date BETWEEN p.start_date AND p.end_date
            GROUP BY s2.clerk_name
    );
    

    sql 题目五

    财务咨询顾问的收入统计问题
    金太阳财务咨询服务公司,聘请了一些财务顾问提供财务操作咨询服务,这些顾问都以兼职形式为公司服务,公司将按小时为顾问工作计算薪酬。具体表信息如下:

    a. 顾问信息表 (consultant)

    create table consultant(
        cst_id int primary key,
        cst_name varchar2(30) not null
    );
    insert into consultant values(1, 'david');
    insert into consultant values(2, 'henry');
    insert into consultant values(3, 'mary');
    insert into consultant values(4, 'kent');
    

    b. 顾问费率表 (billings)

    不同级别的顾问,在不同的时期,每小时的收费是不同的,公司会根据情况上调或者下调顾问的小时佣金待遇。

    create table billings(
        cst_id int not null,
        bill_date date not null,
        bill_rate int not null,
        constraint PK_BILLING PRIMARY KEY(cst_id,bill_date),
        constraint FK_BILLING_EMP FOREIGN KEY (cst_id) references consultant(cst_id)
    );
    insert into billings values(1, to_date('2010-1-1' ,'yyyy/mm/dd'),50);
    insert into billings values(2, to_date('2010-1-1' ,'yyyy/mm/dd'),60);
    insert into billings values(3, to_date('2010-1-1' ,'yyyy/mm/dd'),70);
    insert into billings values(4, to_date('2010-1-1' ,'yyyy/mm/dd'),40);
    insert into billings values(1, to_date('2011-1-1' ,'yyyy/mm/dd'),60);
    insert into billings values(4, to_date('2011-1-1' ,'yyyy/mm/dd'),45);
    

    c. 顾问工作情况记录表 (hoursworked)

    create table hoursworked(
         list_id int primary key, 
         cst_id int not null,
         work_date date not null,
         bill_hrs  decimal(5,2) not null,
         constraint FK_HW_EMP FOREIGN KEY (cst_id) references consultant(cst_id)
       );
    insert into hoursworked values(1,1, to_date('2010-7-1','yyyy/mm/dd'),3);
    insert into hoursworked values(2,1, to_date('2010-8-1','yyyy/mm/dd'),5);
    insert into hoursworked values(3,2, to_date('2010-7-1','yyyy/mm/dd'),2);
    insert into hoursworked values(4,1, to_date('2011-7-1','yyyy/mm/dd'),4);
    insert into hoursworked values(5,3, to_date('2011-8-1','yyyy/mm/dd'),3.5);
    insert into hoursworked values(6,4, to_date('2010-9-1','yyyy/mm/dd'),10);
    insert into hoursworked values(7,4, to_date('2011-8-1','yyyy/mm/dd'),6);
    

    题目

    我们编写一个SQL查询语句,显示顾问的名字以及其总的顾问费用。

    求解

    select c.cst_id, e.cst_name, sum(d.bill_rate*c.bill_hrs) total_fee from (
         select a.cst_id, a.work_date, max(b.bill_date) bill_date, a.bill_hrs
         from billings b inner join hoursworked a
         on a.cst_id=b.cst_id and a.work_date>=b.bill_date
         group by a.cst_id, a.work_date, a.bill_hrs
        ) c, billings d, consultant e
    where c.cst_id=d.cst_id and c.bill_date=d.bill_date and c.cst_id=e.cst_id
    group by c.cst_id,e.cst_name
    order by c.cst_id;
    

    sql 题目六

    ABC在线销售公司业务系统

    表结构

    1、表名:t_category (商品类别表)
    字段(字段名/类型/长度):
    类别编号 category_id INT
    类别名称 category_name VARCHAR2(30)

    2、表名:t_goods (商品表)
    字段(字段名/类型/长度):
    商品编号 goods_no CHAR(3)
    商品名称 goods_name VARCHAR2(30)
    商品价格 goods_price number(7,2)
    所属类别 goods_category INT
    点击次数 goods_click_num INT

    3、 表名: t_saleinfo (销售信息表)
    字段(字段名/类型/长度):
    销售流水号 sid INT
    商品编号 goods_no CHAR(3)
    销售日期 sale_date date
    销售数量 quantity INT
    销售金额 amount number(10,2)

    题目

    1、查询酒类商品的总点击量
    2、查询各个类别所属商品的总点击量,并按降序排列
    3、查询所有类别中最热门的品种(点击量最高),并按点击量降顺序排列
    4、查询茅台的销售情况,按日期升序排列

    格式如下:
    商品编号 商品名称 销售日期 销售数量 销售金额 累计数量 累计金额
    1 茅台 2011-12-1 10 7000 10 7000
    1 茅台 2011-12-2 15 10500 25 17500

    建表

    create table t_category(
       category_id int primary key,
       category_name varchar2(30)
    );
    
    create table t_goods(
       goods_no char(3) primary key,
       goods_name varchar2(30) not null,
       goods_price number(7,2) not null,
       goods_category int not null,
       goods_click_num int default 0,
       constraint FK_GOODS_CATEGORY FOREIGN KEY (goods_category) references t_category(category_id)
    );
    
    create table t_saleinfo(
       sid int primary key,
       goods_no char(3) not null,
       sale_date date  not null,
       quantity int not null,
       amount number(10,2) not null,
       constraint FK_SALEINFO_GOODS FOREIGN KEY (goods_no) references t_goods(goods_no)
    );
    
    -- 增加类别数据
    insert into t_category values(1,'酒类');
    insert into t_category values(2,'服装');
    insert into t_category values(3,'书籍');
    
    -- 商品数据
    insert into t_goods values('G01','贵州茅台',550.56,1,128);
    insert into t_goods values('G02','福建老酒',5.43,1,24);
    insert into t_goods values('G03','泸州老窖',90.56,1,67);
    insert into t_goods values('G04','剑南春',80.56,1,88);
    insert into t_goods values('G05','七匹狼夹克',350.56,2,348);
    insert into t_goods values('G06','七匹狼衬衫',105.43,2,908);
    insert into t_goods values('G07','七匹狼男长裤',130.50,2,167);
    insert into t_goods values('G08','七匹狼领带',280.00,2,388);
    insert into t_goods values('G09','J2EE开发',50.50,3,236);
    insert into t_goods values('G10','STRUTS应用',24.50,3,654);
    insert into t_goods values('G11','ORACLE 11G',100.50,3,145);
    insert into t_goods values('G12','dotnet技术',80.00,3,988);
    
    -- 销售数据
    insert into t_saleinfo values(1,'G01',to_date('2008-1-1','yyyy-MM-dd'),50,50*550.56);
    insert into t_saleinfo values(2,'G01',to_date('2008-1-2','yyyy-MM-dd'),25,25*550.56);
    insert into t_saleinfo values(3,'G01',to_date('2008-1-3','yyyy-MM-dd'),31,31*550.56);
    insert into t_saleinfo values(4,'G01',to_date('2008-1-4','yyyy-MM-dd'),43,43*550.56);
    insert into t_saleinfo values(5,'G01',to_date('2008-1-5','yyyy-MM-dd'),55,55*550.56);
    insert into t_saleinfo values(6,'G01',to_date('2008-1-6','yyyy-MM-dd'),102,102*550.56);
    insert into t_saleinfo values(7,'G11',to_date('2008-1-6','yyyy-MM-dd'),82,82*100.5);
    insert into t_saleinfo values(8,'G11',to_date('2008-1-7','yyyy-MM-dd'),202,202*100.5);
    

    求解

    1、查询酒类商品的总点击量

    select '酒类' category_name,sum(goods_click_num) total_click from t_goods
    where goods_category in (
        select category_id from t_category
    	where category_name='酒类'
    );
    

    2、查询每个类别所属商品的总点击量,并按降序排列

    select a.goods_category,b.category_name,sum(a.goods_click_num) total_click
    from t_goods a inner join t_category b on a.goods_category = b.category_id
    group by goods_category,category_name
    order by sum(a.goods_click_num) desc;
    

    3、 查询所有类别中最热门的品种(点击量最高),并按点击量降顺序排列

    select c.category_id, c.category_name, b.goods_no, b.goods_name, a.max_click
    from (
        select goods_category, max(goods_click_num) max_click from t_goods
        group by goods_category
    )a, t_goods b, t_category c
    where a.goods_category=b.goods_category 
    and a.max_click=b.goods_click_num 
    and c.category_id=a.goods_category
    order by a.max_click desc;
    

    4、查询茅台的销售情况,按日期升序排列

    select d.goods_no, d.goods_name, e.category_name, c.*
    from
    (
        select max(a.goods_no) goods_no, a.sale_date,a.quantity day_quantity,
    		max(a.amount) day_amount, sum(b.quantity) total_quantity, sum(b.amount) total_amount
        from t_saleinfo a inner join t_saleinfo b
        on a.goods_no=b.goods_no and a.goods_no=(
            select goods_no from t_goods where goods_name='贵州茅台'
        ) and a.sale_date>=b.sale_date
        group by a.sale_date,a.quantity
        order by a.sale_date
    )c,t_goods d, t_category e
    where c.goods_no=d.goods_no and d.goods_category=e.category_id;
    
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  • 原文地址:https://www.cnblogs.com/xzh0717/p/11107352.html
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