char* 应用, 去除字符串内多余空格, 用算法而非库函数

问题: 一个已知的字符数组，把里面多余的空格去掉，得到一个新的字符数组，如{a, , ,b,c, , , ,d}变成{a, b,c, ,d}

要求: 不能使用临时数组，时间复杂度为O(n)

#include <iostream>
#include <string>
using namespace std;

void fun2(char* cArr){	int iSpaceCounter = 0;	int iSpaceMarker = -1;	int iNotSpaceMarker = -1;	int iNotSpace = -1;	bool bMeetNotSpace = false;	for(int i = 0; i<strlen(cArr); ++i)	{				if(cArr[i] == ' ')		{			++iSpaceCounter;					if(iSpaceCounter == 2 && bMeetNotSpace)			{				iSpaceMarker = i;			}			else if(i == 0)			{				iSpaceMarker = 0;			}		}		else		{			if(iSpaceCounter > 1 || !bMeetNotSpace)			{				char temp = cArr[i];				cArr[i] = cArr[iSpaceMarker];				cArr[iSpaceMarker] = temp;   				iNotSpace = iSpaceMarker;				iSpaceCounter -= 2;				if(iSpaceCounter < 0)				{					iSpaceCounter = 0;				}				iSpaceMarker += 2;							}			else			{				iNotSpace = i;			}						bMeetNotSpace = true;		}	}	cArr[iNotSpace+1] = '\0';}int main(int argc, char *args[]){ char* cTar = NULL; char* cTemp = " a      b  c"; char* cArr = new char[]; strcpy(cArr,cTemp); fun2(cArr);}