2017人人网面试带通配符*字符串匹配

package match;


//遇到*考虑三种情况 匹配0个字符，匹配1个字符匹配多个字符
//其对应的情况分别是dp[i][j]=dp[i-1][j]||dp[i-1][j-1]||dp[i][j-1]
//其他dp[i][j]=dp[i-1][j-1]&&两个字符相等



import java.util.Scanner;
public class Main {
    public static void main(String []args){
        Scanner sc=new Scanner(System.in);
        while(sc.hasNext()){
            String p=sc.next();      //带*字符串
            String q=sc.next();        //要匹配的字符串
            boolean dp[][]=new boolean[p.length()+1][q.length()+1];
            dp[0][0]=true;
            for(int i=1;i<p.length()+1;i++){
                for(int j=1;j<q.length()+1;j++){
                    if(p.charAt(i-1)=='*'){
                        dp[i][j]=dp[i-1][j]||dp[i-1][j-1]||dp[i][j-1];
                    }
                    else{
                        dp[i][j]=dp[i-1][j-1]&&(p.charAt(i-1)==q.charAt(j-1));
                    }
                }
            }
            System.out.println(dp[p.length()][q.length()]);
        }
    }
}