传送门:http://poj.org/problem?id=3461
Oulipo
Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces. So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap. Input The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
Output For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T. Sample Input 3 BAPC BAPC AZA AZAZAZA VERDI AVERDXIVYERDIAN Sample Output 1 3 0 Source |
KMP模板:
1 #include <cstdio> 2 #include <iostream> 3 #include <cstring> 4 #include <algorithm> 5 #define INF 0x3f3f3f3f 6 #define LL long long 7 using namespace std; 8 const int MAXN = 1e6+10; 9 const int MAXW = 1e4+10; 10 char W[MAXW], T[MAXN]; 11 int wlen, tlen; 12 int nxt[MAXW]; 13 14 void get_Next() 15 { 16 int j = 0, k = -1; 17 nxt[0] = -1; 18 while(j < wlen){ 19 if(k == -1 || W[j] == W[k]){ 20 nxt[++j] = ++k; 21 } 22 else k = nxt[k]; 23 } 24 } 25 26 int KMP_count() 27 { 28 int ans = 0, j = 0; 29 if(wlen == 1 && tlen == 1){ 30 if(W[0] == T[0]) return 1; 31 else return 0; 32 } 33 get_Next(); 34 for(int now = 0; now < tlen; now++){ 35 while(j > 0 && T[now] != W[j]) 36 j = nxt[j]; 37 if(W[j] == T[now]) j++; 38 if(j == wlen){ 39 ans++; 40 j = nxt[j]; 41 } 42 } 43 return ans; 44 } 45 46 int main() 47 { 48 int T_case; 49 scanf("%d", &T_case); 50 while(T_case--){ 51 scanf("%s%s", &W, &T); 52 wlen = strlen(W); 53 tlen = strlen(T); 54 55 printf("%d ", KMP_count()); 56 } 57 return 0; 58 }