zoukankan      html  css  js  c++  java
  • 1025 PAT Ranking (25)(25 point(s))

    problem

    Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged immediately after the test. Now it is your job to write a program to correctly merge all the ranklists and generate the final rank.
    
    Input Specification:
    
    Each input file contains one test case. For each case, the first line contains a positive number N (<=100), the number of test locations. Then N ranklists follow, each starts with a line containing a positive integer K (<=300), the number of testees, and then K lines containing the registration number (a 13-digit number) and the total score of each testee. All the numbers in a line are separated by a space.
    
    Output Specification:
    
    For each test case, first print in one line the total number of testees. Then print the final ranklist in the following format:
    
    registration_number final_rank location_number local_rank
    
    The locations are numbered from 1 to N. The output must be sorted in nondecreasing order of the final ranks. The testees with the same score must have the same rank, and the output must be sorted in nondecreasing order of their registration numbers.
    
    Sample Input:
    
    2
    5
    1234567890001 95
    1234567890005 100
    1234567890003 95
    1234567890002 77
    1234567890004 85
    4
    1234567890013 65
    1234567890011 25
    1234567890014 100
    1234567890012 85
    Sample Output:
    
    9
    1234567890005 1 1 1
    1234567890014 1 2 1
    1234567890001 3 1 2
    1234567890003 3 1 2
    1234567890004 5 1 4
    1234567890012 5 2 2
    1234567890002 7 1 5
    1234567890013 8 2 3
    1234567890011 9 2 4
    

    tip

    answer

    #include <cstdio>
    #include <algorithm>
    #include <vector>
    using namespace std;
    struct student {
        long long int no;
        int score, finrank, loca, locarank;
    };
    bool cmp1(student a, student b) {
        return a.score != b.score ? a.score > b.score : a.no < b.no;
    }
    int main() {
        int n, m;
        scanf("%d", &n);
        vector<student> fin;
        for(int i = 1; i <= n; i++) {
            scanf("%d", &m);
            vector<student> v(m);
            for(int j = 0; j < m; j++) {
                scanf("%lld %d", &v[j].no, &v[j].score);
                v[j].loca = i;
            }
            sort(v.begin(), v.end(), cmp1);
            v[0].locarank = 1;
            fin.push_back(v[0]);
            for(int j = 1; j < m; j++) {
                v[j].locarank = (v[j].score == v[j - 1].score) ? (v[j - 1].locarank) : (j + 1);
                fin.push_back(v[j]);
            }
        }
        sort(fin.begin(), fin.end(), cmp1);
        fin[0].finrank = 1;
        for(int j = 1; j < fin.size(); j++)
            fin[j].finrank = (fin[j].score == fin[j - 1].score) ? (fin[j - 1].finrank) : (j + 1);
        printf("%d
    ", fin.size());
        for(int i = 0; i < fin.size(); i++)
            printf("%013lld %d %d %d
    ", fin[i].no, fin[i].finrank, fin[i].loca, fin[i].locarank);
        return 0;
    }
    

    experience

    • 就是道简单的模拟题,能不能快一点做完?
  • 相关阅读:
    多线程等待
    多线程多进程
    Django中的 返回json对象的方式
    爬虫之 单线程+多任务异步协程
    python 调用github的api,呈现python的受欢迎的程度
    爬虫之线程池
    爬虫之代理和cookie的处理
    pip 安装报错
    git 新建仓库第一次提交
    ansible的剧本
  • 原文地址:https://www.cnblogs.com/yoyo-sincerely/p/9339029.html
Copyright © 2011-2022 走看看