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  • 20. Valid Parentheses

    Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.

    The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]" are not.


    括号匹配,遍历string,碰到左括号把左括号入栈,碰到右括号出栈,判断出栈的字符和右括号是否匹配。

    public class Solution {
        public boolean isValid(String s) {
            Stack<Character> stack = new Stack<Character>();
            for (int i = 0; i < s.length(); i++) {
                switch (s.charAt(i)) {
                    case '(':
                    case '{':
                    case '[':
                        stack.push(s.charAt(i));
                        break;
                    case ')':
                        if (stack.empty() || stack.pop() != '(') {
                            return false;
                        }
                        break;
                    case '}':
                        if (stack.empty() || stack.pop() != '{') {
                            return false;
                        }
                        break;
                    case ']':
                        if (stack.empty() || stack.pop() != '[') {
                            return false;
                        }
                        break;
                }
            }
            if (stack.empty()) {
                return true;
            } else {
                return false;
            }
        }
    }
    
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  • 原文地址:https://www.cnblogs.com/yuchenkit/p/7169505.html
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